<span>This can be solved using basic algebra. X equals the number of liters of 2% brine to add. Therefore we use this equation. 3 + 0.02x = 2.4 + 0.08x 0.6 = 0.6x x = 0..6/0.06 x = 10</span>
Answer:
Energy transfers to the metal from the water and calorimeter until they are all at room temperature.
Explanation:
i hope this helps
Answer:
39.2 g
Explanation:
- 2Ni₂O₃(s) ⟶ 4Ni(s) + 3O₂(g)
First we <u>convert 55.3 grams of Ni₂O₃ into moles of Ni₂O₃</u>, using its<em> molar mass</em>:
- 55.3 g ÷ 165.39 g/mol = 0.334 mol Ni₂O₃
Then we <u>convert 0.334 moles of Ni₂O₃ into moles of Ni</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:
- 0.334 mol Ni₂O₃ *
= 0.668 mol Ni
Finally we <u>calculate how much do 0.668 Ni moles weigh</u>, using the<em> molar mass of Ni </em>:
- 0.668 mol Ni * 58.69 g/mol = 39.2 g