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3 years ago

Oceanography does not include the study of which of the following topics?

Chemistry

1 answer:

MrRissso [65]3 years ago

5 0

Answer:

A. The relationship between the Sun,Moon,and Earth

Explanation:

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Cuprite, Cu2O, has a body-centered cubic unit cell of oxide anions with four copper cations in a tetrahedral arrangement around

MrMuchimi

Answer: The coordination number of Cu+ is two while the coordination number of O2- is 4

Explanation:

The coordination number of an ion in a unit cell arrangement refers to the number of immediate neighboring ions of opposite charge surrounding a particular ion. In Cu2O, the charge on Cu is +1 and the charge on the oxide ion is -2. Each copper I ion is surrounded by two oxide ions while each oxide ion is surrounded by four copper I ions in each unit cell.

8 0

4 years ago

Round 65.145 meters to 4 significant figures

nydimaria [60]

<span>145 * 10^4

There's your answer. Good luck my friend.</span>

4 0

4 years ago

Someone please help me with this

igor_vitrenko [27]

Answer:

I think A should be the answer because oxygen is the chemical change of carbon.

7 0

3 years ago

Provide two written definitions of an oxidation-reduction reaction and for each definition tell which reactant is reduced and wh

vesna_86 [32]

Answer:

Explanation:

Oxidation:

1) Oxidation involve the removal of electrons.

2) Oxidation occur when oxidation state of atom of an element is increased.

Reduction:

1) Reduction involve the gain of electron.

2) Reduction is occur when number of electrons increased in an atom and oxidation state decreased.

Consider the following reactions.

4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O → CO₂ + H₂

the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄ → Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

The most comprehensive definition is 2nd definition which involves the increase or decrease in oxidation state.

4 0

4 years ago

A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur

dsp73

Answer:

12.8 g of $O_{2}$ must be withdrawn from tank

Explanation:

Let's assume $O_{2}$ gas inside tank behaves ideally.

According to ideal gas equation- $PV=nRT$

where P is pressure of $O_{2}$ , V is volume of $O_{2}$ , n is number of moles of $O_{2}$ , R is gas constant and T is temperature in kelvin scale.

We can also write, $\frac{V}{RT}=\frac{n}{P}$

Here V, T and R are constants.

So, $\frac{n}{P}$ ratio will also be constant before and after removal of $O_{2}$ from tank

Hence, $\frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}$

Here, $\frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm}$ and $P_{after}=17atm$

So, $n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol$

So, moles of $O_{2}$ must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of $O_{2}$ = 32 g/mol

So, mass of $O_{2}$ must be withdrawn = $(32\times 0.40)g=12.8g$

7 0

3 years ago