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Andrei [34K]
3 years ago
9

9a^4+3a^2+21 please answer

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
8 0
3(a^4+a^2+7) the answer to the question
SSSSS [86.1K]3 years ago
4 0
What are you trying to find?
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A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B
Goshia [24]

A, B and C working together will finish same piece of work in 10 days

A can do a piece of work in 20 days. That is A is doing the work at a rate of  1 / 20. Therefore

B = 1 / 30

C = 1 / 60

A, B and C working togehter their rate will be added together =

A + B + C =  1 / 20 + 1 / 30 + 1 / 60 = 1 / 10

so they can work together to finish same piece of work in 10 days

4 0
2 years ago
Find the surface area of the prism. Please help this is over due
meriva

Answer:

171.125

Step-by-step explanation:

5 0
3 years ago
Suppose a certain manufacturing company produces connecting rods for 4- and 6-cylinder automobile engines using the same product
gregori [183]

Answer:

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder  to  W_4 or  0 is  

     x_4 \le W_4 *  s_4

    x_4 \le 5000 *  s_4

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder  to  W_6 or  0  is  

     x_6 \le W_6 *  s_6

     x_6 \le 8,000 *  s_6

Generally the constrain that limits the production of connecting rods  for both 4 cylinder and 6 cylinders  is

     x_4 \le W_4 *  s_6

=>   x_4 \le 5000 *  s_6

     x_4 \le W_6 *  s_4

=>    x_4 \le 8000 *  s_4

     s_4 + s_6 = 1

The minimum cost of production for next week is  

   U  =  M_4 *  x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6

=>  U  =  13x_4 + 16x_6 + 2000 s_4 + 3500 s_6

Step-by-step explanation:

The cost for the four cylinder production line is  C_4 =  \$2,100

The cost for the six cylinder production line is  C_6 = \$3,500

The manufacturing cost for each four cylinder is  M_4= \$13

 The manufacturing cost for each six cylinder is M_6= \$16

  The weekly production capacity for 4 cylinder connecting rod is W_4 = 5,000

   The weekly production capacity for 6 cylinder connecting rod is W_6 = 8,000

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder  to  W_4 or  0 is  

     x_4 \le W_4 *  s_4

    x_4 \le 5000 *  s_4

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder  to  W_6 or  0  is  

     x_6 \le W_6 *  s_6

     x_6 \le 8,000 *  s_6

Generally the constrain that limits the production of connecting rods  for both 4 cylinder and 6 cylinders  is

     x_4 \le W_4 *  s_6

=>   x_4 \le 5000 *  s_6

     x_4 \le W_6 *  s_4

=>    x_4 \le 8000 *  s_4

     s_4 + s_6 = 1

The minimum cost of production for next week is  

   U  =  M_4 *  x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6

=>  U  =  13x_4 + 16x_6 + 2000 s_4 + 3500 s_6

3 0
4 years ago
Percents and numbers​
n200080 [17]

Answer:

16

Step-by-step explanation:

4 0
3 years ago
How do you simplify 8+9x​
bagirrra123 [75]

Answer:

72x

Step-by-step explanation:

8+(9x)

the distributive proprotey

add the variable "x"

8 0
3 years ago
Read 2 more answers
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