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3 years ago

How do you find the domain & range for #f(T)=sec(piT/4)#?

Mathematics

1 answer:

allsm [11]3 years ago

5 0

Domain and range of what? im not seeing a set of numbers id be happy to help tho

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Let f(x)=25x2−2 .

avanturin [10]

We are given function f(x) = 25x^2 -2.

g(x) is a vertical stretch of f(x) by a factor of 2.

We know, the transformation rule

y= k f(x), vertical stretch by a factor k. For k>0.

Because function f(x) is being vertical stretched by a factor of 2. So, we need to multiply f(x) function by 2.

Therefore, g(x) = 2 f(x) = 2*(25x^2-2).

Therefore, g(x) = 2*(25x^2-2) or g(x) = 50x^2-4.

8 0

3 years ago

Read 2 more answers

5) A farmer raises turkeys and pigs. There are 15 animals all together. The farmer

nika2105 [10]

Answer:

2 pigs, 13 turkeys

Step-by-step explanation:

34=2t+4p (equation for legs)

t+p=15 (equation for total # of animals) --> t=15-p

substitution:

34=2(15-p)+4p

p=2

plug back in to other equation

t=15-(2)

t= 13

6 0

2 years ago

Use the substitution method to solve the system of equations. Choose the

GenaCL600 [577]

Answer:

D. (2,5)

Step-by-step explanation:

For X:

2+2(5)=12

2+10=12

For Y:

5=2+3

5 0

3 years ago

Read 2 more answers

Raul had 56 bouncy balls. he puts 3 times as many balls into red gifts bags as he puts into green gift bags. If he puts the same

Radda [10]

The answer is 3 ÷ 56 = 18 or Raul puts 18 balls in 3 bags.

5 0

3 years ago

Honey and Money are twin brothers. Mother wants to equally divide a rectangular shaped cake of 5cm wide and 6cm long. Find the l

tatuchka [14]

Answer:

Length of rectangular cake = 5 cm

Breadth of rectangular cake = 6 cm

Area of rectangle = 5 cm × 6 cm =30 cm²

If cake is equally distributed between Honey and Money, then areas of two parts should be equal.

So, Amount of cake that Honey and money got $\frac{30}{2}=15$

Share of each (Honey and Money)=15 cm²

So, if the third cake if it was cut diagonally ,the cake must have some height.

Let the height of cake be H.

So, Height of third cake $=\sqrt{L^2+B^2+H^2}\\\\=\sqrt{5^2+6^2+H^2}\\\\=\sqrt{61+H^2}$

If , H=0 that is height is negligible having 0 thickness,

Then the Length of third cake, which is divided into two parts=√61=7.81 cm

5 0

3 years ago