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4 years ago

Algebraic expressions

Mathematics

1 answer:

Ede4ka [16]4 years ago

7 0

Answer:

10y^2-3xy+6x

Step-by-step explanation:

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John ran three laps around his school Johns coach wrote the following notes describing Johns performance

mamaluj [8]

Answer:

18.8 minuites

Step-by-step explanation:

20% of 5 is 1 so the second time is 6 and 30% of 6 is 1.8 so it will be

5+6+7.8=18.8

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2 years ago

X^2-8x-36=0 solve by completing the square ANSWER ASAP

larisa86 [58]

Answer:

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3 years ago

Find (f ∘ g)(-6) when f(x) = 9x + 2 and g(x) = -9x2 - 2x + 1.

Salsk061 [2.6K]

Given that the two functions are $f(x)=9x+2$ and $g(x)=-9x^2-2x+1$

We need to determine the value of $(f \circ g)(-6)$

The value of $(f \circ g)(x)$ :

The value of $(f \circ g)(x)$ can be determined using the formula,

$(f \circ g)(x)=f[g(x)]$

Substituting $g(x)=-9x^2-2x+1$ in the above formula, we get;

$(f \circ g)(x)=f[-9x^2-2x+1]$

Now, substituting $x=-9 x^{2}-2 x+1$ in the function $f(x)=9x+2$ , we get;

$(f \circ g)(x)=9(-9x^2-2x+1)+2$

$(f \circ g)(x)=-81x^2-18x+9+2$

$(f \circ g)(x)=-81x^2-18x+11$

Thus, the value of $(f \circ g)(x)$ is $(f \circ g)(x)=-81x^2-18x+11$

The value of $(f \circ g)(-6)$ :

The value of $(f \circ g)(-6)$ can be determined by substituting x = -6 in the function $(f \circ g)(x)=-81x^2-18x+11$

Thus, we have;

$(f \circ g)(-6)=-81(-6)^2-18(-6)+11$

$(f \circ g)(-6)=-81(36)-18(-6)+11$

$(f \circ g)(-6)=-2916+108+11$

$(f \circ g)(-6)=-2797$

Thus, the value of $(f \circ g)(-6)$ is -2797

Hence, Option B is the correct answer.

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4 years ago

Select all the statements that are correct rational approximation of irrational numbers?

eimsori [14]

The answers would most likely be A,C,and B from my calculations

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4 years ago

Reyna has 7 coins worth 5 cents each and 3 coins worth 10 cents each.

DerKrebs [107]

Found this. Hope it helps.

https://www.algebra.com/algebra/homework/word/coins/Word_Problems_With_Coins.faq.question.1059726.html

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4 years ago

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