Answer:
2√5
Step-by-step explanation:
The radius is the distance from the center to a point anywhere along the edge of the circle. To find the distance between these two points, use the distance formula.
![d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(1--3)^2 + (2-4)^2}\\ d = \sqrt{4^2 + -2^2}\\ d = \sqrt{16 + 4}\\ d = \sqrt{20} \\d = 2\sqrt{5}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%5C%5Cd%20%3D%20%5Csqrt%7B%281--3%29%5E2%20%2B%20%282-4%29%5E2%7D%5C%5C%20d%20%3D%20%5Csqrt%7B4%5E2%20%2B%20-2%5E2%7D%5C%5C%20d%20%3D%20%5Csqrt%7B16%20%2B%204%7D%5C%5C%20d%20%3D%20%5Csqrt%7B20%7D%20%5C%5Cd%20%3D%202%5Csqrt%7B5%7D)
The dimensions of the rectangular pen should be 15 by 20 feet and the maximum area is 1200 square feet.
Let the area be y .
Area = (base) × (height)
Base = 2x
Height = h
Let the area of the rectangular pens be y .
∴ y = 2xh
Perimeter of all the fencing = 4x+3h
∴ 4x+3h = 120
now we solve for h
3h = 120-4x
h = 40 - 4/3 x
Now we will substitute this value in the above first equation:
y = 2xh
or, y = 2x (40 - 4/3 x)
or, y = 80x - 8/3 x²
Now for the maximum area we have to find the first order differentiation of y
now,
dy /dx = 80 - 16/3 x
At dy/dx = 0 we get the value of x for which y is maximum.
80 - 16/3 x = 0
or, - 16/3 x = -80
or, x = 15 feet
Hence height = 40 - 4/3 x = 40 - 20 = 20feet
Maximum area = 2xh = 2×15×40 = 1200 square feet
The dimensions of the rectangular pen should be 15 by 20 feet and the maximum area is 1200 square feet.
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Answer:
5:2
Step-by-step explanation:
There are 5 apples and 2 cherries. Put them together to get 5:2.