Answer:
Step-by-step explanation:
Velocity is the change in displacement of an object.
Velocity = dh/dt
Given the equation modelled by the height travelled by the area as h=-5t^2+60t
v = dh/dt = -10t + 60
At the maximum height, the velocity is zero i.e. -10t+60 =0
-10t = -60
t = 6secs
Substituting t = 6 secs into the modeled equation to know how high the arrow goes;
h=-5t^2+60t
h = -5(6)²+60(6)
h = -180+360
h = 180m
Hence, the arrow travels 180m high.
To determine how long that the arrow stays in flight, we will apply the formula:
H = ut+1/2gt²
180 = 60t+1/2(9.8)t²
180 = 60t +4.9t²
49t²+600t -1800 = 0
t = -600±√600²-4(49)(-1800)/98
t = -600±√360000+352800/98
t = -600±√712800/98
t = -600+844.28/98
t = 244.28/98
t = 2.49secs
Hence, the arrow stays 2.49secs in the flight.
