Recall the equation for a circle with center ( h , k ) (h,k) and radius r r. At what point in the first quadrant does the line w
ith equation y = 2.5 x + 2 y=2.5x+2 intersect the circle with radius 6 and center (0, 2)?
1 answer:
Equation of this circle is
x^2 + (y - 2)^2 = 36
y = 2.5x + 2
Substitute for y in the equation of the circle:-
x^2 + (2.5x + 2 - 2)^2 = 36
x^2 + 6.25x^2 = 36
x^2 = 36 / 7.25
x = +/- 6 / 2.693 = +/- 2.228
when x = 2.228 y = 2.5(2.228) + 2 = 7.57 to nearest hundredth
when x = -2.228 y = 2.5(-2.228) + 2 = -3.57
So they intersect at 2 points but the intersect in the first quadrant is at (2.23, 7,57) to nearest hundredth.
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