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4 years ago

A number chosen at random from 1 to 10 find the probability of selecting a 5 or greater

Mathematics

1 answer:

ZanzabumX [31]4 years ago

8 0

The probablility is 1/2 or 0.50 % chance.

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PLEASE HELP!! GIVING BRAINLIEST!!!!!

Slav-nsk [51]

Answer:

your answer will be C)117

Step-by-step explanation:

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3 years ago

Read 2 more answers

Solve for x: -2x + 11 = 23 6 -6 12 -12

zheka24 [161]

Answer:

x = -6

Step-by-step explanation:

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3 years ago

Can someone help me with 5, 8 and 9?

worty [1.4K]

5. b1= 8, b2= 11+9=20, h= 15, A= 210

8. b1= 4, b2= 10, h= 5.2, A= 36.4

9. b1= 7, b2= 13, h= 4.2, A= 42

8 0

3 years ago

Need help with geometric sequence quick 30 points!!!!

hram777 [196]

The explicit formula for given geometric sequence is:

$a_n = 6 . 5^{n-1}$

Step-by-step explanation:

Given geometric sequence is:

6,30,150,750....

First of all we will find the common ratio.

Common ratio is the ratio between two consecutive terms of a geometric sequence

In the given sequence

a1 = 6

a2 = 30

a3 = 150

a4 = 750

Now

$r=\frac{a_2}{a_1} = \frac{30}{6} = 5\\r=\frac{a_3}{a_2} = \frac{150}{30} = 5$

The explicit formula for geometric sequence is:

$a_n = a_1 . r^{n-1}$

Putting the values of a1 and r

$a_n = 6 . 5^{n-1}$

Keywords: Geometric sequence

Learn more about geometric sequence at:

#LearnwithBrainly

7 0

3 years ago

8. Colleen times her morning commute such that there is an equal likelihood that she will arrive early or late to work on any gi

Lubov Fominskaja [6]

Solution :

Case I :

If Collen is late on $0$ out of $5$ days.

$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}$

$$=\frac{1}{32}$

Case II :

When Collen is late on $1$ out of $5$ days.

$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_1$

$=\frac{1}{32} \times 5$

$$=\frac{5}{32}$

Case III :

When Collen was late on $2$ out of $5$ days.

$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_2$

$=\frac{1}{32} \times 10$

$$=\frac{5}{16}$

Therefore, the $\text{probability}$ that Collen will arrive late to work no more than $\text{twice}$ during a $\text{five day workweek}$ is :

$=\frac{1}{32} + \frac{5}{32} + \frac{5}{16}$

$=\frac{1}{2}$

3 0

3 years ago