We need to first find the molarity of Ba(OH₂) solution.
A mass of 3.24 mg is dissolved in 1 L solution.
Ba(OH)₂ moles dissolved - 3.24 x 10⁻³ g/171.3 g/mol = 1.90 x 10⁻⁵ mol
dissociaton of Ba(OH)₂ is as follows;
Ba(OH)₂ --> Ba²⁺ + 2OH⁻
1 mol of Ba(OH)₂ dissociates to form 2OH⁻ ions.
Therefore [OH⁻] = (1.90 x 10⁻⁵)x2 = 3.8 x 10⁻⁵ M
pOH = -log[OH⁻]
pOH = -log (3.8 x 10⁻⁵)
pOH = 4.42
pH + pOH = 14
therefore pH = 14 - 4.42
pH = 9.58
Mole fraction is the ratio of the constituent moles to the total constituents. The mole fraction of sodium chloride is 0.0443.
<h3>What is a mole fraction?</h3>
A mole fraction is the proportion of the moles of the component in a total component present.
In 100 gm of solution 13.0 5 means, there is 13.0 gm of sodium chloride present. The mass of water is calculated as,
100 - 13.0 = 87.0 gm
Moles of sodium chloride is calculated as:

Moles of water are calculated as:

Now, moles fraction is calculated by dividing moles of sodium chloride by total moles as,

Therefore, the mole fraction of sodium chloride is 0.0443.
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Answer:
FC of C = -1
General Formulas and Concepts:
- Lewis Dot Structures
- Resonance Structures
- Formal Charge: FC = # of valence e⁻ - # of lone e⁻ - # of bonds
Explanation:
<u>Step 1: Define</u>
Carbon (C)
- 4 valence e⁻
- 2 lone e⁻
- 3 bonds
Oxygen (O)
- 6 valence e⁻
- 2 lone e⁻
- 3 bonds
<u>Step 2: FC of C</u>
- Substitute: FC = 4e⁻ - 2e⁻ - 3
- Subtract: FC = -1