Answer:
The mass of CaCO3 reacted is 5.00 grams
Explanation:
Step 1 :Data given
Before the reaction, the container, including the CaCO3, had a mass of 24.20 g
After the reaction the container with product had a mass of only 22.00 g because the CO2 gas produced did not remain in the container.
Molar mass of CO2 = 44.01 g/mol
Molar mass CaCO3 = 100.09 g/mol
Step 2: The balanced equation
CaCO3 → CaO + CO2
Step 3: Calculate mass of CO2
Mass of CO2 = 24.20 grams - 22.00 grams
Mass of CO2 = 2.20 grams
Step 4: Calculate moles CO2
Moles CO2 = mass CO2 / molar mass CO2
Moles CO2 = 2.20 grams / 44.01 g/mol
Moles CO2 = 0.0500 moles
Step 5: Calculate moles CaCO3
For 1 mol CaCO3 we'll have 1 mol CaO and 1 mol CO2
For 0.0500 moles CO2 we need 0.0500 moles CaCO3
Step 6: Calculate mass CaCO3
Mass CaCO3 = moles CaCO3 * molar mass CaCO3
Mass CaCO3 = 0.0500 moles * 100.09 g/mol
Mass CaCO3 = 5.00 grams
The mass of CaCO3 reacted is 5.00 grams
