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san4es73 [151]
3 years ago
9

When determining an element’s chemical properties, the most important subatomic particle to look at is

Chemistry
1 answer:
GrogVix [38]3 years ago
5 0
The answer is F. protons
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How does soil structure affect the characteristics of soil? a. It determines the acidity of soil. b. It determines the available
7nadin3 [17]

Answer:

B

Explanation:

Soil structure affects water and air movement in a soil, nutrient availability for plants, root growth, and microorganism activity. ... This allows for greater air and water movement and better root growth.

4 0
3 years ago
Which type of radioactive decay can pass through the body? A.alpha emission B.beta emission C.positron emission D.gamma rays
TEA [102]
A beta emission radioactive decay can pass through the body.
5 0
3 years ago
2. When heated above 500 ºC, potassium nitrate decomposes according to the equation below. 4KNO3 2K2O + 2N2 + 5O2A.If oxygen is
AysviL [449]

Answer:

(a) The rate of formation of K2O is 0.12 M/s.

The rate of formation of N2 is also 0.12 M/s

(b) The rate of decomposition of KNO3 is 0.24 M/s

Explanation:

(a) From the equation of reaction, the mole ratio of K2O to O2 is 2:5.

Rate of formation of O2 is 0.3 M/s

Therefore, rate of formation of K2O = (2×0.3/5) = 0.12 M/s

Also from the equation of reaction, mole ratio of N2 to O2 is 2:5.

Rate of formation of N2 = (2×0.3/5) = 0.12 M/s

(b) From the equation of reaction, mole ratio of KNO3 to O2 is 4:5.

Therefore, rate of decomposition of KNO3 = (4×0.3/5) = 0.24 M/s

3 0
3 years ago
A radioactive nuclide that is used for geological dating has an atomic number of 19 and mass number 40. Which is the symbol of t
Alina [70]
The mass number goes on top, and the atomic number goes on bottom. 
Therefore, the answer is C:
40
     K
19

7 0
4 years ago
Read 2 more answers
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten c
gtnhenbr [62]

Answer:

1.13 × 10⁶ g

Explanation:

Let's consider the reduction of aluminum (III) from Al₂O₃ to pure aluminum.

Al³⁺ + 3 e⁻ → Al

We can establish the following relations:

  • 1 Ampere = 1 Coulomb / second
  • The charge of 1 mole of electrons is 96,468 c (Faraday's constant)
  • 1 mole of Al is produced when 3 moles of electrons circulate
  • The molar mass of Al is 26.98 g/mol.

The mass of aluminum produced under these conditions is:

90.0 s \times \frac{1s}{620c} \times \frac{96,468c}{1mole^{-} } \times \frac{3mole^{-}}{1molAl} \times \frac{26.98gAl}{1molAl} =1.13 \times 10^{6} g Al

6 0
4 years ago
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