(x-2) Divided By (x^3-4x^2+ 6x-4) long divison

Identify the variable expression that is not a polynomial. A. 23 B. + 2 C. y + 1 D. x12

myrzilka [38]

A polynomial consists of several terms so A.23

4 0

2 years ago

Which comparison is not correct?

strojnjashka [21]

Answer:

the 2 one is wrong

Step-by-step explanation:

the 2 would be greater than the 9 sense both the numbers are negative and the bigger the negative number is the less amount it is so -9 is smaller than -2

8 0

2 years ago

Ricardo works in the marketing department of a game design company. His boss has offered to bonus the entire department of their

Stells [14]

Answer:

<h2>Approximately 4824 games </h2>

Step-by-step explanation:

Given that the sales made are 4,567 ,5430, 3998, 5,220,and 4,906

the average is (4567+5430+3998+5220+4906)/5

=24121/5

=4824.2

in the month of august let the sales be x

average= (4567+5430+3998+5220+4906+x)/6

the average for march to july is 4824.2

4824.2= (4567+5430+3998+5220+4906+x)/6

24121+x=4824.2*6

24121+x=28945.2

x=28945.2-24121

x=4824.2

approximately 4824 games

4 0

2 years ago

The distribution of weights for newborn babies is approximately normally distributed with a mean of 7.4 pounds and a standard de

blsea [12.9K]

Answer:

1. 15.87%

2. 6 pounds and 8.8 pounds.

3. 2.28%

4. 50% of newborn babies weigh more than 7.4 pounds.

5. 84%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 7.4 pounds

Standard Deviation, σ = 0.7 pounds

We are given that the distribution of weights for newborn babies is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

1.Percent of newborn babies weigh more than 8.1 pounds

P(x > 8.1)

$P( x > 8.1) = P( z > \displaystyle\frac{8.1 - 7.4}{0.7}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 8.1) = 1 - 0.8413 = 0.1587 = 15.87\%$

15.87% of newborn babies weigh more than 8.1 pounds.

2.The middle 95% of newborn babies weight

Empirical Formula:

Almost all the data lies within three standard deviation from the mean for a normally distributed data.
About 68% of data lies within one standard deviation from the mean.
About 95% of data lies within two standard deviations of the mean.
About 99.7% of data lies within three standard deviation of the mean.

Thus, from empirical formula 95% of newborn babies will lie between

$\mu-2\sigma= 7.4-2(0.7) = 6\\\mu+2\sigma= 7.4+2(0.7)=8.8$

95% of newborn babies will lie between 6 pounds and 8.8 pounds.

3. Percent of newborn babies weigh less than 6 pounds

P(x < 6)

$P( x < 6) = P( z > \displaystyle\frac{6 - 7.4}{0.7}) = P(z < -2)$

Calculation the value from standard normal z table, we have,

$P(x < 6) =0.0228 = 2.28\%$

2.28% of newborn babies weigh less than 6 pounds.

4. 50% of newborn babies weigh more than pounds.

The normal distribution is symmetrical about mean. That is the mean value divide the data in exactly two parts.

Thus, approximately 50% of newborn babies weigh more than 7.4 pounds.

5. Percent of newborn babies weigh between 6.7 and 9.5 pounds

$P(6.7 \leq x \leq 9.5)\\\\ = P(\displaystyle\frac{6.7 - 7.4}{0.7} \leq z \leq \displaystyle\frac{9.5-7.4}{0.7})\\\\ = P(-1 \leq z \leq 3)\\\\= P(z \leq 3) - P(z < -1)\\= 0.9987 -0.1587= 0.84 = 84\%$

84% of newborn babies weigh between 6.7 and 9.5 pounds.

7 0

3 years ago

Triangle Q S R is shown. Angle Q S R is a right angle. Altitude s is drawn from point S to point T on side Q R to form a right a

Neko [114]

*The diagram is in the attachment

Answer:

q = 2√14

Step-by-step explanation:

To determine the value of q, apply the leg rule/geometric mean theorem, which is:

Hypotenuse/leg = leg/part

Hypotenuse = 10 + 4 = 14

Leg = q

Part = 4

Plug in the values into the equation:

14/q = q/4

Cross multiply

q*q = 14*4

q² = 56

q = √56

q = √(4*14)

q = 2√14

4 0

2 years ago

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