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MrMuchimi
3 years ago
5

A parabola has a maximum value of 4 at x= -1, a y-intercept of 3, and an x-intercept of 1.

Mathematics
2 answers:
Scilla [17]3 years ago
7 0

well none of the answer choices match up with all these statements ...

C. it only matches up with the y-intercept given

D. it matches with the y-intercept, and the x- intercept is not quite on the 1

*but i would say C is the closest, because it has an x-intercept of -1 and the maximum point is at (1,4) ... which are the same with the given statements except that they have opposite signs, but yeah i have no clue*

4vir4ik [10]3 years ago
7 0

Answer:

The answer is C

Step-by-step explanation:

Plz mark as Brainliest

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The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)

The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)

Answer: The system of inequalities would produce the region indicated on the graph is Option B

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3 years ago
Please help me with this pre algebra question
Nikolay [14]

Answer: 11

Step-by-step explanation:

The sum of 8 and 3

Sum is the same as addition.

Therefore, the equation is 8+3

Solve 8+3

8+3=11

6 0
3 years ago
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