When microbial action during decomposition in aquatic ecosystems removes too much oxygen, the body of water experiences

2 answers:

7 0

N and P limitation is strongest in aquatic ecosystems (because light and water isn't) governed by same principles as terrestrial ecosystems radically different environmental controls streams have been treated as "sewers of terrestrial ecosystems" yet stream ecosystems have their own characteristics generated by the interaction of biota with the physical and chemical properties of the system unlike terrestrial ecosystems, nutrients "spiral" rather than cycle. The more limiting the nutrient, the tighter the spiral. Detritus/heterotrophs <---> autotrophs.

Ilya [14]3 years ago

6 0

The right answer is Eutrophication.

Eutrophication occurs mainly in ecosystems with slowly changing waters, especially in deep lakes.

In the depths of the lake, where dead algae are deposited, the aerobic bacteria that feed on them proliferate in turn, consuming more and more oxygen. However, in the absence of sufficient water circulation, which is often the case in a deep lake, the lake bottom is poorly oxygenated and the bacteria eventually deplete the oxygen in the deep water layers. They can no longer degrade all the dead organic matter and it accumulates in the sediments. The lake is said to be aging. Such a situation, when it occurs, worsens when it is hot because the solubility of oxygen in water (like that of all gases) decreases as the temperature increases.

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larisa [96]

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alexandr1967 [171]

Answer:

C. Broca's Area

Explanation:

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3 years ago

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Svetlanka [38]

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A geneticist is studying two genes. each gene can be either dominant or recessive. a sample of 100 individuals is categorized as

Aleksandr-060686 [28]

Attached is a table. I found the exercise on another page on the internet and the sample of 100 individuals was categorised on a table - easier to understand than as it is presented here.
"(a) what is the probability that a random sampled individual, gene 1 is dominant" - We should first add up all of the individuals that are dominant for gene 1 (56+24) and then divide it by the total number of individuals (100).
 $\frac{56+24}{100}$ =0.8
The probability is of 8 in 10 individuals.
"(b) what is the probability that a random sampled individual, gene 2 is dominant" - Follow the same logic as in the previous question.
 $\frac{56+14}{100}$ =0.7
The probability is of 7 in 10 individuals.
"(c) given that gene 1 is dominant, what is the probability that gene 2 is dominant" - Because we are considering those that are dominant for gene 1, our total number of individuals is the total individuals that are dominant for gene 1 and not the whole 100. Once we have this restriction, and we want to know the probability that gene 2 is dominant in these individuals, we should also only consider those that are dominant for gene 2.
 $\frac{56}{56+24}$ =0.7
The probability that gene 2 is dominant, given that that gene 1 is dominant, is of 7 in 10 individuals.

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4 years ago

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Kaylis [27]

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