Answer:
a) For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:
Where a and b represent the limits of the distribution.
b) 
And the height for this case would be 0.125
Step-by-step explanation:
Part a
For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:
Where a and b represent the limits of the distribution.
Part b
For this case the density function would be given by:
And the height for this case would be 0.125
And 
for other case.
The cumulative distribution function would be given by:
What are you trying to do here?
Solve the graph, or make it appear as something else?
First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0
sec (x) (2sec (x) -2) = 0
Then we're going to separate the two to find the zeros of each because anything time 0 is zero.
sec(x) = 0
2sec (x) - 2 = 0
Now, let's simplify the second one as the first one is already.
Add 2 to both sides:
2sec (x) = 2
Divide by 3 on both sides:
sec (x) = 1
I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
<span>x = 2, y = 1
= 3*2 + 7*1
= 6+7
= 13
Hence, (2, 1) is the answer.</span>
Equation::
value + value = value
80x + 60(50-x) = 74*50
----
80x + 60*50 - 60x = 74*50
----
20x = 14*50
x = 35 lbs (amt. of 80 cent tea to use)
50-x = 15 lbs (amt. of 60 cent tean to use)
