3 years ago

PLEASE HELP! I WILL GIVE YOU THANKS EACH TIME ON YOUR PROFILE.

Mathematics

1 answer:

ch4aika [34]3 years ago

5 0

Which question to answer?

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Solutions are (6,3) and (-2,3).

Step-by-step explanation:

From the first equation given we can write:

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substituting for $(x-2)^{2}$ in the second equation given we get

$\frac{16-(y-3)^{2}}{16} + \frac{(y-3)^{2}}{64} = 1$

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Putting y=3 in the first equation we get

$(x-2)^{2} = 16$

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