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artcher [175]
3 years ago
10

An animal lays eggs with a tough, leathery, watertight shell. This adaptation would be best suited for which environment?

Physics
2 answers:
Burka [1]3 years ago
3 0
Swampy environments I hope this helps
Leni [432]3 years ago
3 0

The answer to this question is desert!!

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During a solar eclipse, the Moon is positioned directly between Earth and the Sun. Find the magnitude of the net gravitational f
dezoksy [38]

Answer:

F= 2.3733 x10^{20} N

Explanation:

Let's define the variables to proceed with the operations,

So,

The masses

M_ {sun} = 1.99 * 10^{30} Kg

M_ {Earth} = 5.98 * 10 ^ {24} Kg

M_ {Moon} = 7.36 * 10 ^{22} Kg

Average distances

\bar {x} _ {Sun \rightarrow Earth} = 1.5 * 10 ^ {11} m

\bar {x} _ {Earth \rightarrow Moon} = 3.84 * 10 ^ 8m

Gravitational constant

G = 6.67 * 10^ {-11} \frac {Nm ^ 2} {kg ^ 2}

The formula of the Gravitational Force between the Moon and the Earth would be,

F = \frac {GM_ {Earth} M_ {Moon}} {(\bar {x} _ {Earth \rightarrow Moon}) ^ 2}

F= \frac{(6.67*10^{-11} \frac{Nm^2}{kg^2})(5.98*10^{24}Kg)(7.36*10^{22}Kg)}{(3.84*10^8m)^2}

F = 1.9908 * 10 ^{20} N

This force is in the direction of the earth.

We perform the same process but now between the Sun and the Moon, like this,

F_2 = \frac {GM_ {Sun} M_ {Moon}} {(\bar {x} _ {Sun \rightarrow Earth} - \bar {x} _ {Earth \rightarrow Moon}) ^ 2}

F_2 = \frac{(6.67*10^{-11} \frac{Nm^2}{kg^2})(1.99*10^{30}Kg)(7.36*10^{22}Kg)}{(1.5*10^{11}m-3.84*10^8m)^2}

F_2 = 4.3641*10^-{ 20} N

This force is in the direction of the Sun

The net force must be

F_ {net} = F_2-F

F_ {net} = 2.3733*10^{20} N

This in the direction of the Sun.

8 0
3 years ago
Make the following conversion:
katrin2010 [14]

Answer:

Kelvin to Celsius: C = K - 273 (C = K - 273.15 if you want to

6 0
2 years ago
Density and volume of 1000
Dimas [21]

Answer:

A cell wall is a structural layer surrounding some types of cells, just outside the cell membrane. It can be tough, flexible, and sometimes rigid. It provides the cell with both structural support and protection, and also acts as a filtering mechanism.

8 0
3 years ago
A 1550 kg car located at < 319, 0, 0 > m has a momentum of < 45000, 0, 0 > kg·m/s. What is its location 10 s later?
Serggg [28]

Answer:

< 45319, 0, 0 > m

Explanation:

mass, m = 1550 kg

r = < 319, 0, 0 > m

v = < 4500, 0, 0 > m/s

t = 10 s

distance traveled in 10 second is

d =  v x t

d = < 4500 x 10, 0 x 10, 0 x 10 > m

d = < 45000, 0, 0 > m

So, the new location of the car is

r' = r + d = < 319, 0, 0 > + < 45000, 0, 0 >

r' = < 45319, 0, 0 > m

5 0
3 years ago
A urine sample has a mass of 151 g and a density of 1.020 g / mL . What is the volume of this sample?
babymother [125]

Answer:

0.15 L.

Explanation:

Density of a substance is defined as a property of a substance which is the mass of unit volume of substance. Its SI unit is kg/m3.

Density = mass/volume

Mass = 151 g

Density = 1.020 g/ml

To find volume,

= 151/1.020

= 148.04 ml

Converting ml to liters,

1000 ml = 1 liter,

148.04 ml = 0.148 l

= 0.15 L.

6 0
3 years ago
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