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mariarad [96]
3 years ago
10

What mass of sucrose, c12h22o11, is needed to make 500.0 ml of 0.200 m solution?

Chemistry
2 answers:
brilliants [131]3 years ago
6 0
34.2 I hope it helps


lara31 [8.8K]3 years ago
5 0

<u>Answer:</u> The mass of sucrose is 34.23 g

<u>Explanation:</u>

Molarity is defined as the number of moles present in one liter of solution.

Mathematically,

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Or,

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 0.200 M

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 500 mL

Mass of sucrose = ? g

Putting values in above equation, we get:

0.200mol/L=\frac{\text{Mass of sucrose}\times 1000}{342.3g/mol\times 500mL}\\\\\text{Mass of sucrose}=34.23g

Hence, the mass of sucrose is 34.23 g

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The reaction is:

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mole of Cl2 = 0.16 /2 = 0.08 mol

Mass of Cl2

m /70 = 0.08 = 5.6 g

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Determine the volume of a substance that has a density of 1.84 g/ml and a mass of 12 grams
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3 years ago
The process where a substance reacts with oxygen
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Answer:

The process where substance react with oxygen is called combustion.

Explanation:

When substance react with oxygen combustion is occur. The substance which burned is called fuel and in this process large amount of heat is released to the surrounding. It is exothermic process.

For example:

4Li + O₂    →      2Li₂O

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  S +  O₂      →      SO₂  

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3 years ago
How many liters of carbon dioxide will 0.5 moles of lithium hydroxide (LiOH) absorb?
Elden [556K]

Answer : The volume of carbon dioxide will be, 5.6122 L

Solution : Given,

Moles of LiOH = 0.5 moles

Molar mass of carbon dioxide = 44 g/mole

Density of carbon dioxide = 0.00196 g/ml

First we have to calculate the mass of carbon dioxide.

The balanced reaction will be,

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From the reaction we conclude that

As, 2 moles of LiOH absorbs 44 grams of carbon dioxide

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Mass of carbon dioxide = 11 g

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Now we have to calculate the volume of carbon dioxide.

Density=\frac{Mass}{volume}

0.00196g/ml=\frac{11g}{volume}

Volume of carbon dioxide = 5612.24 ml = 5.6122 L      (1 L = 1000 ml)

Therefore, the volume of carbon dioxide will be, 5.6122 L

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