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OLEGan [10]
3 years ago
12

Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)

Chemistry
1 answer:
ZanzabumX [31]3 years ago
8 0

Answer:

limiting reactant

Explanation:

<em>The term that will be used to describe zinc in this case is </em><em>limiting reactant.</em>

A limiting reactant is a reactant that determines the amount of product formed in a chemical reaction. They are often stoichiometrically smaller of all the reactants in a reaction and once they are used up during, the reaction stops.

In this case, the zinc metal in the reaction is completely consumed, making the hydrochloric acid to be in excess. The zinc thus determines the amount of the products formed,

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If we were to dissolve iodine in alcohol, which term would describe the alcohol?
marishachu [46]
It will be Solvent the term that would describe the alcohol will be solvent.
4 0
4 years ago
In many species, a transition metal has an unusually high or low oxidation state. Write balanced equations for the following and
dedylja [7]

When `CO_(2)` is bubbled through a cold pasty solution of barium peroxide in water, `H_(2)O_(2)` is obtained. <br> `BaO+CO_(2)+H_(2)OtoBaCO_(3)+H_(2)O_(2)` Barium carbonate being insoluble is filtered off. This is known as Merck's process.

<h3>What is meant by Perhydrol?</h3>

perhydrol (countable and uncountable, plural perhydrols) A stabilised solution of hydrogen peroxide.

<h3>What is Merck's Perhydrol?</h3>

Uses: Perhydrol is used as an antiseptic for wounds, and also acts as a germicide to kill bacteria and germs.

Being a strong oxidizing agent it has bleaching properties and acts as a ripening agent.

Learn more about merck's process here:

<h3>brainly.com/question/16856280</h3><h3 /><h3>#SPJ4</h3>

7 0
2 years ago
A chemist prepares a solution of calcium bromide CaBr2 by measuring out 4.81μmol of calcium bromide into a 50.mL volumetric flas
Mariana [72]

Answer:

The concentration of the CaBr2 solution is 96 µmol/L

Explanation:

<u>Step 1:</u> Data given

Moles of Calciumbromide (CaBr2) = 4.81 µmol

Volume of the flask = 50.0 mL = 0.05 L

<u>Step 2:</u> Calculate the concentration of Calciumbromide

Concentration CaBr2 = moles CaBr2 / volume

Concentration CaBr2 = 4.81 µmol / 0.05 L

Concentration CaBr2 = 96.2 µmol /L = 96.2 µM

The concentration of the CaBr2 solution is 96 µmol/L

4 0
4 years ago
What is the morality of 2.50 L of solution that contains 1.85 mol of anhydrous sodium tetraborate?
Lyrx [107]
That would just be 1.85 mol divided by 2.5L. So 0.74 mol/L or 0.74 M.
6 0
3 years ago
Which model of the atom is thought to be true?
Fed [463]

Answer:

I wanna  say C.

Explanation:

3 0
4 years ago
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