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forsale [732]
3 years ago
14

Calculate the number of atoms in 4.8 dm^3 of neon gas at rtp

Chemistry
1 answer:
WINSTONCH [101]3 years ago
4 0

No of atoms in 4.8 dm³ of neon gas is determined in the following way.

Explanation:

We have given

Neon Gas=4.8dm³

At STP

1 mole of an ideal gas occupies 22.4 L(dm³) of volume.

which means that  number of molecules occupy 22.4 L of volume.

So

4.8 dm³x 1 mole/22.4 dm³ = 0.214 moles Neon

0.214 moles x 6.02x10²³ atoms/mole = 1.29x10²³ atoms of Neon

No of Atoms in 4.8dm3 neon gas =1.29x10²³ atoms of Neon

To know more about this :

https://brainly.in/question/2122177

https://brainly.in/question/2419625

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For the reaction below, initially the partial pressure of all 3 gases is 1.0atm. . 2NH3(g)--&gt; N2(g) + 3H2(g) K, 0.83 1. When
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Answer:

The reaction would shift toward the reactants

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Explanation:

For the reaction:

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<h3>The reaction would shift toward the reactants</h3><h3>When the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm</h3>

<em />

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