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3 years ago

Calculate the number of atoms in 4.8 dm^3 of neon gas at rtp

Chemistry

1 answer:

WINSTONCH [101]3 years ago

4 0

No of atoms in 4.8 dm³ of neon gas is determined in the following way.

Explanation:

We have given

Neon Gas=4.8dm³

At STP

1 mole of an ideal gas occupies 22.4 L(dm³) of volume.

which means that number of molecules occupy 22.4 L of volume.

4.8 dm³x 1 mole/22.4 dm³ = 0.214 moles Neon

0.214 moles x 6.02x10²³ atoms/mole = 1.29x10²³ atoms of Neon

No of Atoms in 4.8dm3 neon gas =1.29x10²³ atoms of Neon

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A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce

spin [16.1K]

Explanation:

The given data is as follows.

Volume of lake = $15 \times 10^{6} m^{3}$ = $15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}$

Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = $5.6 \times 15 \times 10^{9} mg$

= $84 \times 10^{9}$ mg

= $84 \times 10^{3}$ kg

Flow rate of river is 50 $m^{3} sec^{-1}$

Volume of water in 1 day = $50 \times 10^{3} \times 86400 liter$

= $432 \times 10^{7}$ liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are $2.9792 \times 10^{10} mg$ or $2.9792 \times 10^{4} kg$

Flow rate of sewage = $0.7 m^{3} sec^{-1}$

Volume of sewage water in 1 day = $6048 \times 10^{4}$ liter

Concentration of sewage = 300 mg/L

Total amount of pollutants = $1.8144 \times 10^{10} mg$ or $1.8144 \times 10^{4}kg$

Therefore, total concentration of lake after 1 day = $\frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l$

= 6.8078 mg/l

$k_{D}$ = 0.2 per day

$L_{o}$ = 6.8078

Hence, $L_{liquid}$ = $L_{o}(1 - e^{-k_{D}t}$

$L_{liquid}$ = $6.8078 (1 - e^{-0.2 \times 1})$

= 1.234 mg/l

Hence, the remaining concentration = (6.8078 - 1.234) mg/l

= 5.6 mg/l

Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.

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3 years ago

Goodwin County has plenty of water. The residents of Goodwin County enjoy fishing, boating, and swimming in Goodwin Lake. The Go

MrRa [10]

Answer:

I am pretty sure it is a watershed

Explanation:

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2 years ago

Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 264 mL .

gavmur [86]

The formula for density is:

D = m/v

We can use the formula to figure out the mass because we already know two of the three values (we are given the density and volume), so we only have to solve for m. If we plug our given values into the formula, we get:

2.70 = m / 264

Now, all we need to do is solve for m. The goal is to get m on one side of the equation, and all we have to do is multiply each side of the equation by 264:

264 × 2.70 = (m÷264) × 264

264 × 2.70 = m

m = 712.8

The mass of the piece of aluminum is 712.8 grams.

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3 years ago

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Ket [755]

The correct answer is D.

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3 years ago

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tekilochka [14]

Answer:

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