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Simora [160]
3 years ago
12

Describe how transpiration and respiration show interactions among Earth's system

Chemistry
2 answers:
stepladder [879]3 years ago
7 0

Earth has 4 systems/ spheres which are known as Lithosphere(land), Biosphere(living things), Hydrosphere(water) and Atmosphere(air).

Transpiration is the process that interact with the Hydrosphere and Respiration is the process that interacts with the Atmosphere.

Transpiration is the process happening in plants which absorb and distribute water through their roots and release water in the form of vapors through their leaves. As this process involves Water, therefore this process interacts with the Hydrosphere.  

Respiration is the process in which plants convert carbon dioxide to oxygen as a part of photosynthesis which was then inhaled by the animals. As this process involves Air, therefore this process interacts with the Atmosphere.

melamori03 [73]3 years ago
5 0
Transpiration is when a plant and soil absorbs water while respiration is when plants convert carbon dioxide into oxygen.This shows interactions with Earth by talking about plants and rocks also part of soil which are part of Earth (unless you think they aren't)

i know this is not really helpful but i tried
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Pls help I don’t understand at all
galina1969 [7]

Answer:

Mass = 12.48 g

Explanation:

Given data:

Mass of sulfur dioxide = 25.0 g

Mass of sulfur formed = ?

Solution:

Chemical equation:

SO₂      →        S   + O₂

Number of moles of SO₂:

Number of moles = mass/molar mass

Number of moles = 25.0 g / 64.07 g/mol

Number of moles = 0.39 mol

Now we will compare the moles of SO₂  with S.

                     SO₂        :          S

                        1          :           1

                       0.39     :         0.39

Mass of sulfur:

Mass = number of moles × molar mass

Mass = 0.39 mol × 32 g/mol

Mass = 12.48 g

4 0
3 years ago
If you had 100 ml of juice how many milliters would be fruit juice
raketka [301]
The answer would be 1000
8 0
3 years ago
What is the nuclear binding energy of an atom that has a mass defect of 5.0446
notsponge [240]

Answer:

<em>Option C: 4.54 x </em>10^{11}<em> KJ/mol of nuclei</em>

<em>Note: </em>Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}.

Explanation:

If mass defect is known, then nuclear binding energy can easily be calculated, here's how:

First step is to convert that mass defect into kg.

Mass defect = 5.0446 amu

Mass defect = 5.0466 x 1.6606 x 10^{-27}

Because 1 amu = 1.6606 x 10^{-27} Kg.

<em>Mass defect = 8.383 x </em>10^{-27}<em> kg.</em>

Now, we need to find out it's energy equivalent by using following equation:

Using the equation E = mc²:

where c= 3.00 x 10^{8} m/s²

E = (8.383 x 10^{-27}) x (3.00 x 10^{8})²

E = 7.54 x 10^{-10} J  this energy is in Joules but nuclear binding energy is usually expressed in KJ/mol of nuclei. Let's convert it:

(7.54 x 10^{-10} Joule/nucleus)x(1 kJ/1000 Joule)x(6.022 x 10^{23} nuclei/mol) =  

<em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em>

E = <em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em> So, this is the nuclear binding energy of that atom, which is option  C.

<em>Note:</em> Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}

4 0
3 years ago
Read 2 more answers
Guys please help me with this question!
damaskus [11]
A reducing agent is one which is oxidised in the reaction itself. When you take into account the oxidation numbers you will see that the Cl- ions are oxidised from an oxidation number of -1 to 0 in Cl2. Therefore Cl- ions are the reducing agent.
3 0
3 years ago
Refer to the two formulas for xylose.
Ludmilka [50]

Answer:

A is the molecular formula for xylose because shows the actual number of atoms in the compound: Formula B is the empirical formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the molecular formula for xylose because shows the arrangement of atoms in the compound: Formula B is the structurab formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the empirical formula for xylose because it shows the actual number of atoms in the compound: Formula B is the molecular formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the structural formula for xylose because it shows the arrangement of atoms in the compound: Formula B is the empirical formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound.

5 0
2 years ago
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