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Tomtit [17]
3 years ago
9

Nuclear energy can be used to power _______.

Physics
1 answer:
hoa [83]3 years ago
6 0
<span>Nuclear power plants produce radioactive waste that must be stored properly. It is very impossible for a nuclear power plant to have no waste at all since lots of chemicals are used to create the process as it gives energy to other machines. Nuclear energy can be used to power all of the above choices. Radioactive waste can not be released into local water supplies since the wastes are very radioactive and may cause mutation to the fishes and bioaccumulation which will affect humans as well. It will also cause air pollution if the chemicals are not stored properly.</span>
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For each star, determine how its light would be shifted. Not all choices may be used, and some may be used more than once. A red
barxatty [35]

Answer:

Explanation:

To calculate the red shift you use the following formula:

z=\frac{1+vcos\theta/c}{\sqrt{1-v^2/c^2}}-1

\tetha: angle between the observer and the motion of the body

v: speed of the body

c: speed of light

for motion with angle 90° (transversal motion):

z=\sqrt{\frac{c+v}{c-v}}-1

- A red dwarf moving away from Earth at 39.1 km/s :

z=\sqrt{\frac{3*10^8m/s+39.1*10^3m/s}{3*10^8m/s-39.1*10^3m/s}}-1=1.3*10^{-4}

- A yellow dwarf moving transversely at 15.1 km/s (angle = 90°):

z=\frac{1+0}{\sqrt{1-(15.1*10^3m/s)^2/(3*10^8m/s)^2}}-1=1.27*10^{-9}

- A red giant moving towards Earth at 23.3 km/s (angle = 0°):

z=\frac{1+(23.3*10^3m/s)/(3*10^8m/s)}{\sqrt{1-(23.3*10^3m/s)^2/(3*10^8m/s)^2}}-1=7.76*10^{-5}

- A blue dwarf moving away from Earth at 25.9 km/sz=\frac{1+(25.9*10^3m/s)/(3*10^8m/s)}{\sqrt{1-(25.9*10^3m/s)^2/(3*10^8m/s)^2}}-1=8.63*10^{-5}

- A red dwarf moving transversely at 14.1 km/s

z=\frac{1+0}{\sqrt{1-(14.1*10^3m/s)^2/(3*10^8m/s)^2}}-1=1.11*10^{-9}

6 0
4 years ago
What kind of energy transformation takes place in a generator?
STALIN [3.7K]

Answer:

B. mechanical to electrical

3 0
3 years ago
A drill bit in a hand drill is turning at 1200 revolutions per minute (1200 rpm). Express this angular speed in radians per seco
ankoles [38]

Answer:

the answer will be about 126 rad/s

Explanation:

3 0
2 years ago
The club was in contact with a ball, initially at rest, for about 0.0045 s. If the ball has a mass of 55 g and leaves the head o
luda_lava [24]

Answer:

0.38 kN

Explanation:

From newton's second law of motion,

F = m(v-u)/t........................ Equation 1

Where F = Average force exerted on the ball, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time of contact.

Given: m = 55 g = 55/1000 = 0.055 kg, v = 102 ft/s = (102×0.3048) m/s = 31.0896 m/s, u = 0 m/s (initially at rest), t = 0.0045 s

Substitute into equation 1

F = 0.055(31.0896-0)/0.0045

F = 1.709928/0.0045

F = 379.984 N

F ≈ 0.38 kN

8 0
4 years ago
Read 2 more answers
The law of repulsion by Coulomb agrees with: Newton's law of universal gravitation Newton's laws of motion the findings of Gilbe
s344n2d4d5 [400]

Explanation:

The law of repulsion is given by Coulomb. The mathematical form of Coulomb law is given by :

F=\dfrac{kq_1q_2}{r^2}...............(1)

Where

F is the force

k is the electrostatic constant

q_1\ and\ q_2 are electric charges

r is the distance between charges

The Newton's law of universal gravitation is given by :

F=\dfrac{Gm_1m_2}{r^2}..............(2)

G is the universal gravitational constant

From equation (1) and (2) it is clear that both law obeys inverse square law and both are of same type. So, the law of repulsion by Coulomb agrees with the Newton's law of universal gravitation.

7 0
4 years ago
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