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2 years ago

Find the volume of the square pyramid. A. 15 yd B. 25 yd C. 35 yd D. 45 yd

Mathematics

1 answer:

notsponge [240]2 years ago

6 0

45 yd. Area Is BH. the area of the base is 9. Times the height, 5, is 45

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Members of the drama club spend $795 on t-shirts and sweatshirts for a play.They purchase 20 more tshirts than sweatshirts.They

Anika [276]

Answer:

The drama club bought 35 t-shirt

Step-by-step explanation:

Let

t-shirt = x

Sweatshirt = y

Total cost = $795

They purchase 20 more tshirts than sweatshirts

x = y + 20

The equation is:

12x + 25y = 795

12(y + 20) + 25y = 795

12y + 240 + 25y = 795

37y = 795 - 240

37y = 555

y = 15

Substitute y = 15 into

x = y + 20

x = 15 + 20

x = 35

t-shirt = 35

Sweatshirt = 15

The drama club bought 35 t-shirt

8 0

3 years ago

Suppose 86% of 50 people at a law firm like their job. How many people like their job.

solniwko [45]

To find 86% of 50, you do 50*.86 (because .86 is the decimal form of the percentage 86%)

50*.86=43 people

Hope this helps

8 0

3 years ago

Read 2 more answers

Someone please help me

Kitty [74]

Answer:

0.45, 4, 2, 1.5

Step-by-step explanation:

14/3 = 4.66667

Numbers less than 14/3 are 0.45, 4, 2, 1.5.

8 0

2 years ago

Which sentence does not belong with the other 3?

attashe74 [19]

D, there is no division property of equality

7 0

3 years ago

The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

$x+y=5600...(1)$

$y=5600-x...(1)$

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be $40x$ and cost of y end-zone tickets would be $20y$ .

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

$40x+20y=134000...(2)$

Upon substituting equation (1) in equation (2), we will get:

$40x+20(5600-x)=134000$

$40x+112000-20x=134000$

$20x+112000=134000$

$20x+112000-112000=134000-112000$

$20x=22000$

$\frac{20x}{20}=\frac{22000}{20}$

$x=1100$

Therefore, 1100 field side tickets were sold.

Upon substituting $x=1100$ in equation (1), we will get:

$y=5600-1100$

$y=4500$

Therefore, 4500 end-zone tickets were sold.

3 0

3 years ago