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valentina_108 [34]
3 years ago
11

Suppose that Adam rolls a fair six-sided die and a fair four-sided die simultaneously. Let AAA be the event that the six-sided d

ie is an even number and BBB be the event that the four-sided die is an odd number. Using the sample space of possible outcomes below, answer each of the following questions.
Mathematics
1 answer:
sammy [17]3 years ago
5 0

The question is incomplete. Here is the complete question.

Suppose that Adam rolls a fair six-sided die and a fair four-sided die simultaneously. Let A be the event that the six-sided die is an even number and B be the event that the four-sided die is an odd number. Using the sample space of possible outcomes below, answer each of the following questions.

What is P(A), the probabillity that the six-sided die is an even number?

What is P(B), the probability of the four-sided die is an odd number?

What is P(A and B), the probability that the six-sided die is an even number  <em>and</em> the four-sided die is an odd number?

Are events A and B independent?

a) Yes, events A and B are independent events.

b) No, events A and B are not independent events.

Answer: P(A) = 1/2

P(B) = 1/2

P(A and B) = 1/4

a) Yes, events A and B are independent events.

Step-by-step explanation: The event A is related to a six-sided die, so total possibilities is 6.

For a six-sided die to show a even number, there are 3 possibilities: (2,4,6)

so, P(A) = 3/6 = 1/2

The event B is for a 4-sided die, i.e. total possibilities is 4.

To show an odd number, there are 2 possibilities: (1,3).

Then, P(B) = 2/4 = 1/2

Now, the probability of occuring A and B is:

P(A and B) = P(A).P(B)

P(A and B) = 1/2*1/2

P(A and B) = 1/4

The events are <u>independent</u> events because the probability of A happening does not influence the occuring of event B.

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A pet store sold 36 Siamese cats. If the ratio of Siamese cats to house cats sold was 4:9, what is the combined amount of cats s
Dafna11 [192]

 The combined amount of cats sold is 117.

Ratio expresses the relationship between two variables. It shows the frequency of which that one value is contained within another variable.

The ratio of  Siamese cats to house cats = 4 : 9

Number of Siamese cats = 36

Number of combined cats = c

This equation can be formed using the above information:

4/13 x c = 36

4c = 468

c = 468 / 4

c = 117

A similar question was answered here: brainly.com/question/411732

5 0
3 years ago
Jada Elena and Lin walked a total of 37 miles last week. jada walked 4 more miles that elena, and Lin walked 2 more miles than j
MA_775_DIABLO [31]

Answer:

Jada walked 13\ miles

Elena walked 9\ miles

Lin walked 15\ miles

Step-by-step explanation:

Let

x----> total miles walked by Jada

y----> total miles walked by Elena

z----> total miles walked by Lin

we know that

x+y+z=37 -----> equation A

x=y+4 -----> y=x-4 ------> equation B

z=x+2 ------> equation C

Substitute equation C and equation B in equation A and solve for x

x+(x-4)+(x+2)=37

3x=37+2

3x=39

x=13\ mi

Find the value of y

y=13-4=9\ mi

Find the value of z

z=13+2=15\ mi

therefore

Jada walked 13\ miles

Elena walked 9\ miles

Lin walked 15\ miles

3 0
3 years ago
I NEED THE ANSWER TO THIS ASAP FOR A TEST PLEASE!!!!!!!!
Varvara68 [4.7K]

Answer:

192

Step-by-step explanation:

you really should do your own test

A = lwh

A = 6 x 4 x 5 + 3

A = 6 x 4 x 8

A = 192

7 0
3 years ago
32, 28, 21, 31, 18<br><br> Is 18 an outlier or no?
Kryger [21]

Answer:

No because 21 is close to it.

Step-by-step explanation:

To be considered an outlier, it would need to be a farther distance such as the distance from 28 to 21.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

4 0
3 years ago
Read 2 more answers
I have 4 times as much money as my brother has. our total is $55.how much does each of us have?
babymother [125]

Answer:

You have 44$, your brother has 11$.

Step-by-step explanation:

Let x be the amount of money your brother has.

Since you have four times the amount of money your brother has, we can call the amount of money you have 4x.

x+4x=55,\\5x=55,\\x=\boxed{\$11}

Thus, you have:

4(11)=\boxed{\$44}

5 0
2 years ago
Read 2 more answers
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