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puteri [66]
3 years ago
15

PLEASE HELP ME IM SO LOST

Chemistry
1 answer:
fenix001 [56]3 years ago
7 0
I am stuck on this too
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At what phase of mitosis are two separate nuclei are formed as nuclear membranes form around
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Probably telophase because for the difference in the nuclear membrane
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Why is DNA used to show common ancestry ?
Marizza181 [45]

Answer:

while analogous structures show that similar selective pressures can produce similar adaptations (beneficial features). Similarities and differences among biological molecules can be used to determine species' relatedness.

Explanation:

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How many molecules are there in 46.0 g of ethanol, CH 3 CH 2OH?
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3 years ago
Question 7-Which of the following is not an acid-base neutralization reaction?
docker41 [41]

Answer:- It is choice D. H_2SO_4+2NaCl\rightarrow 2HCl+Na_2SO_4

Explanations:- In general, a neutralization reaction is the reaction of an acid with base to form salt and water.

in first reaction the reaction is taking place between ammonia(a base) and hydrochloric acid(an acid) to form their salt(ammonium chloride). So, it is an acid-base neutralization reaction.

In second reaction, sodium hydroxide(a base) is reacting with acetic acid(an acid) to form their salt(sodium acetate) and water. So, it is an acid-base neutralization reaction.

In third reaction, Nitric acid is reacting with calcium hydroxide(a base) to form a salt(calcium nitrate) and water. So, it is an acid-base neutralization reaction.

In fourth reaction, sulfuruc acid is reacting a sodium chloride(a salt) to give a double replacement reaction. It is not an acid-base neutralization reaction as it's not taking place between an acid and base.

So, the correct choice is D. H_2SO_4+2NaCl\rightarrow 2HCl+Na_2SO_4

7 0
4 years ago
Read 2 more answers
It takes 338. kJ/mol to break an carbon-chlorine single bond. Cal broken by absorbing a single photon Iculate the maximum wavele
vodomira [7]

Answer:

354 nm

Explanation:

E=\frac{h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength of the light

So,  Given that:- Energy = 338. kJ/mol = 338000 J/mol

Also, N_a=6.023\times 10^{23}\ {mol}^{-1}

So, Energy for single photon = \frac{338000}{6.023\times 10^{23}}\ J

Applying the values in the above equation as:-

\frac{338000}{6.023\times 10^{23}}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

69\times \:10^{26}\lambda=5^{20}\times \:62770482.511

\lambda=354\times 10^{-9}\ m=354\ nm

5 0
3 years ago
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