Square root are the same 2 numbers multiplied.
Ex: 8*8=64 (Square root is 8)
9*9=81 (Square root is 9)
2.2360679775*2.2360679775=5
Answer=2.2360679775
It would be: a = v₂-v₁ / t
a = (70-10) / 12
a = 60 / 12
a = 5 m/s²
So, option A is your final answer.
Hope this helps!
Primary equation: A(x)= (5y)(3X)
Secondary equation: 5y+3X=1000
y=200-(3X)/5
A(x)=3X(1000-3X)
A(x)=3000X-9X²
Now, find the derivative of A(x) to find the max... here's the work for that, or you could guess and check.
A'(x)=3000-18X
Set derivative equal to 0
0=3000-18X
166.6666666=X
Now test the intervals
(0,166.6666) (166.66666, 1000)
1st derivative is + 1st derivative is -
Plug the X value back into the secondary equation
5y+3(166.666666)=1000
5Y=500
Y=5
Answer:
X= 166.6666666666
Y=5
Please note, this is entry level calculus, and your teacher may expect you to use a different, longer route such as guess and check.
Answer:
one solution: (-1,1)
Step-by-step explanation:
we have
----> equation A
----> equation B
Solve the system by substitution
Substitute equation A in equation B
solve for x
<em>Find the value of y</em>
----> 
The solution is the point (-1,1)
therefore
one solution: (-1,1)
I think x = 1/176
1/2x + 10 = - 1/4x + 54
1/2x + 10 = - 1/4x + 54, x 0
1/2x - 1/4x = 54 - 10
2-1 over 4x = 44
1/4x = 44
1 = 176x
x = 1/176
I could be wrong.
