Answer:
L2: y-0 = 5/2(x-5)
y = 5/2x-25/2
Step-by-step explanation:
Parallel lines have same slopes.
Line 1, L1: 5x-2y=20 is in standard form Ax+By=C therefore slope m1= -A/B = -5/-2 = 5/2 or you can solve it for y so you will have the equation in slope-intercept form.
5x-2y = 20
-2y = -5x+20
y = (-5/-2)x+20/(-2)
y = (5/2)x-10 hence m1=5/2 and y-intercept is -10
Line 2 , L2: y-y1 = m (x-x1), m=m2=m1=5/2
Point p(5,0) or p(x1,y1) therefore x1=5 , y1=0 and m=5/2
L2: y-0 = 5/2(x-5)
y = 5/2x-25/2
For perpendicular lines, m1m2 = -1 or m2 = -1/m1; where m1 and m2 are the slopes of the lines.
Here line 1 is 3x - 7y = 42
7y = 3x - 42
y = 3/7 x - 6; Hence m1 = 3/7
m2 = -1/(3/7) = -7/3
Required equation y - y1 = m2(x - x1)
y - (-8) = -7/3(x - (-3))
y + 8 = -7/3(x + 3)
y + 8 = -7/3 x - 7
y = -7/3 x - 7 - 8
y = -7/3 x - 15
A = lw + πr²
A = (125)(56) + (3.14)(28)²
A = 7000 + 3.14(784)
A = 7000 + 2461.76
A = 9461.76 yd²
Make the picture bigger, can barely see it
