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ruslelena [56]
3 years ago
9

Lesson 4 practice problems.

Mathematics
1 answer:
aivan3 [116]3 years ago
4 0

Answer:

which is the question yours asking help for

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If x+y=6 and xy =2find x³+y³(please help me fast with explanation also please) T^T​
Maurinko [17]

Answer: x³+y³=180

Step-by-step explain:                                                                                            let's remember the formula                                                                                 x³+y³=(x+y)(x²-xy+y²) and also  x³+y³=(x+y)³-3xy(x+y)                                              then                                                                                      \displaystyle\boldsymbol{ x^3+y^3=\underbrace{(x+y)^3}_{6}-3\underbrace{xy}_{2}\underbrace{(x+y)}_6}=\\\\6^3-3\cdot 2\cdot 6=216-36=180                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                

6 0
3 years ago
Rehana has some money after she spend Rs15 she has Three quarter of the initial amount left the amount left is
ludmilkaskok [199]

Answer:

Amount left = Rs 45

Step-by-step explanation:

Let the initial amount be x.

Translating the word problem into an algebraic expression, we have;

x - 15 = \frac {3}{4} * x

x - 15 = \frac {3x}{4}

Cross-multiplying, we have;

4(x - 15) = 3x

4x - 60 = 3x

Rearranging the equation (collecting like terms), we have;

4x - 3x = 60

x = Rs 60

Next, we find the amount left;

Amount left = 60 - 15

Amount left = Rs 45

6 0
3 years ago
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