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horsena [70]
2 years ago
6

If the bar magnet is flipped over and the south pole is brought near the hanging ball, the ball will be?

Physics
1 answer:
disa [49]2 years ago
7 0

The ball may attracted to the magnet.

<h3>How can we understand that the hanging ball will be attracted to the magnet or not?</h3>
  • From the question, we understand that the ball is attracted by the north pole of the bar magnet, then the bar magnet flipped over and the south pole is brought near the hanging ball.
  • As we know, in this type of experiments of bar magnet most of the times the ball is made out of steel.
  • Steel is a magnetic material.
  • Magnetic materials gets attracted  to the magnet at both the North and South pole.
  • This can be compared to how neutral objects also gets attracted to the positively and negatively charged rods through the Polarization force.

So, If the bar magnet is flipped over and the south pole is brought near the hanging ball, The ball will be attracted to the magnet.

Learn more about the bar magnet:

brainly.com/question/27943723

#SPJ4

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6 0
4 years ago
What is the diameter of a 12lb shot if the specific gravity is of the shot iron in the shot is 6.8, the density of fresh water 6
marysya [2.9K]

Answer:

The diameter is 0.378 ft.

Explanation:

Given that,

Mass of shot = 12 lb

Density of fresh water = 62.4 lb/ft

Specific gravity = 6.8

We need to calculate the volume of shot

V = \dfrac{4}{3}\pi r^3\ ft^3

The density of shot is

Using formula of density

\rho = \dfrac{m}{V}

Put the value into the formula

\rho =\dfrac{12}{ \dfrac{4}{3}\pi r^3}

We need to calculate the radius

Using formula of specific gravity

specific\ gravity =\dfrac{density\ of\ shot}{dnsity\ of\ water}

Put the value into the formula

6.8=\dfrac{\dfrac{12}{\dfrac{4}{3}\pi r^3}}{62.4}

r^3=\dfrac{12}{\dfrac{4}{3}\pi\times6.8\times62.4}

r^3=0.0067514

r =(0.0067514)^{\frac{1}{3}}

r=0.1890\ ft

The diameter will be

d = 2\times r

d =2\times0.1890

d =0.378\ ft

Hence, The diameter is 0.378 ft.

7 0
3 years ago
A football field is about 100m long. If it takes a person 20s to run its length, how fast were they running?
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100 m/ 20 s= 5 m/s.

They were running at a speed of 5 m/s~
7 0
3 years ago
A train starts from a station with a constant acceleration of at = 0.40 m/s2. A passenger arrives at the track time t = 6.0s aft
jok3333 [9.3K]

Answer:

4.8 m/s  

Explanation:

When she catches the train,

  1. They will have travelled the same distance.and
  2. Their speeds will be equal

The formula for the distance covered by the train  is

d = ½at² = ½ × 0.40t² = 0.20t²

The passenger starts running at a constant speed 6 s later, so her formula is

d = v(t - 6.0)

The passenger and the train will have covered the same distance when she has caught it, so

(1) 0.20t² = v(t - 6.0)

The speed of the train is

v = at = 0.40t

The speed of the passenger is v.

(2) 0.40t = v

Substitute (2) into (1)

0.20t² = 0.40t(t - 6.0) = 0.40t² - 2.4 t

Subtract 0.20t² from each side

0.20t² - 2.4t = 0

Factor the quadratic

t(0.20t - 2.4) = 0

Apply the zero-product rule

t =0     0.20t - 2.4 = 0

                   0.20t = 2.4

(3)                      t = 12

We reject t = 0 s.

Substitute (3) into (2)

0.40 × 12 = v

            v = 4.8 m/s

The slowest constant speed at which she can run and catch the train is 4.8 m/s.

A plot of distance vs time shows that she will catch the train 6 s after starting. Both she and the train will have travelled 28.8 m. Her average speed is 28.8 m/6 s = 4.8 m/s.

7 0
4 years ago
According to Coulomb’s Law, the force between two charged objects is related to _____. the distance separating them the mass of
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The force between two charges objects is related to separation.


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