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3 years ago

How many grams is 5kg of tap water?

1 answer:

3 0

When you write "5 kg", the little 'k' in the middle stands for 1,000.
So '5 kg' means '5,000 g'.

It doesn't matter what substance you're working with. It could be
tap-water, gold, air, or mud. 5 kg of it is still 5,000 grams of it.

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5. Why does a Ntion try to influence the value of its currency?

Mazyrski [523]

Answer:

If inflation is relatively lower than competitors, then the countries goods will become more attractive and demand will rise. Lower inflation tends to increase the value of the currency in the long term.

Explanation:

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2 years ago

A life preserver is thrown from an helicopter straight down to a person in distress. The initial velocity of the life preserver

Leno4ka [110]

Answer:29.627 m

Explanation:

Given

Initial velocity of life preserver(u) is 1.6 m/s

it takes 2.3 s to reach the water

using equation of motion

v=u+at

$v=1.6+9.81\times 2.3$

v=24.163 m/s

Let s be the height of life preserver

$v^2-u^2=2gs$

$24.163^2-1.6^2=2\times 9.81\times s$

$s=\frac{581.29}{2\times 9.81}$

s=29.627 m

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3 years ago

Fill in the blank

elixir [45]

Is there any types of answer to get an idea

8 0

3 years ago

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A 72-kg skydiver is falling from 10000 feet. At an instant during the fall, the skydiver

MissTica

Answer:

Approximately $2.31\; \rm m \cdot s^{-2}$ (assuming that the acceleration due to gravity is $g = 9.81\; \rm m \cdot s^{-2}$ .)

Explanation:

Assuming that $g = 9.81\; \rm m \cdot s^{-2}$ the weight on this 72-kg skydiver would be $W = m \cdot g = 72 \; \rm kg \times 9.81\; \rm m \cdot s^{-2} = 706.32\; \rm N$ (points downwards.)

Air resistance is supposed to act in the opposite direction of the motion. Since this skydiver is moving downwards, the air resistance on the skydiver would point upwards.

Therefore, the net force on this skydiver should be the difference between the weight and the air resistance on the skydiver:

$\begin{aligned}F(\text{net force}) &= W - F(\text{air resistance})\\ &= 706.32\; \rm N - 540\; \rm N =166.32\; \rm N \end{aligned}$ .

Apply Newton's Second Law of motion to find the acceleration of this skydiver:

$\begin{aligned}a &= \frac{F(\text{net force})}{m} \\ &= \frac{166.32\; \rm N}{72\; \rm kg} = 2.31\; \rm m \cdot s^{-2} \end{aligned}$ .

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3 years ago

During which of the following chemical changes does a precipitate form?

babymother [125]

Answer is B.........

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3 years ago

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