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stepan [7]
2 years ago
12

In a mall, a shopper rides up an escalator between floors. At the top of the escalator, the shopper turns right and walks 6.40 m

to a store. The magnitude of the shopper's displacement from the bottom of the escalator to the store is 16.0 m. The vertical distance between the floors is 6.20 m. At what angle is the escalator inclined above the horizontal?
Physics
1 answer:
Elden [556K]2 years ago
5 0

Answer:

25 degrees above the horizontal.

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<span>Find an activity you enjoy and make it a priority in your schedule.</span>
6 0
3 years ago
Calculate the kinetic energy in joules of an automobile weighing 2135 lb and traveling at 55 mph. (1 mile = 1.6093 km, 1 lb = 45
victus00 [196]
<span>Let's convert the speed to m/s: speed = (55 mph) (1609.3 m / mile) (1 hour / 3600 seconds) speed = 24.59 m/s Let's convert the mass to kilograms: mass = (2135 lb) (0.45359 kg / lb) mass = 968.4 kg We can find the kinetic energy KE: KE = (1/2) m v^2 KE = (1/2) (968.4 kg) (24.59 m/s)^2 KE = 292780 joules The kinetic energy of the automobile is 292780 joules.</span>
4 0
3 years ago
I really need help with this!! Will give brainliest if you help T^T
slava [35]

Answer:

What inferences can you make about the melting points of the different substances and the motion of their particles, based on the data? (ignore that needed it here so i could see it better.)

Explanation:

Butter has a lower melting point than the cheese and the wax. The motion of the cheese were a little separated while the butter articles have more space in between. The wax had the closest particles.

I dont know if that makes sense? 

5 0
2 years ago
Which best describes a value for density
scoray [572]
Density can be any number, as long as it has the right units.

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8 0
3 years ago
Monochromatic light passes through a double slit, producing interference, the distance between the slit centres is 1.2 mm and th
Alik [6]

Answer:

The wavelength of the light is 7200\ \AA.

Explanation:

Given that,

Distance between the slit centers d= 1.2 mm

Distance between constructive fringes \beta= 0.3\ cm

Distance between fringe and screen D= 5 m

We need to calculate the wavelength

Using formula of width

\beta=\dfrac{D\lambda}{d}

Put the value into the formula

0.3\times10^{-2}=\dfrac{5\times\lambda}{1.2\times10^{-3}}

\lambda=\dfrac{0.3\times10^{-2}\times1.2\times10^{-3}}{5}

\lambda=7.2\times10^{-7}\ m

\lambda=7200\ \AA

Hence, The wavelength of the light is 7200\ \AA.

8 0
2 years ago
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