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nataly862011 [7]
3 years ago
11

Happy Valentines Day FR33 points for you guys

Physics
2 answers:
Fed [463]3 years ago
6 0

Answer:

thankkkkkksssssssssssssss

sasho [114]3 years ago
4 0

Answer:

happy diwaliiiii..........

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For every action
kondaur [170]
For every action, there is an equal but opposite reaction. 
8 0
4 years ago
Una cuerda es puesta a vibrar 400 veces en 4 segundos Cual es la frecuencia del sonido emitido?
Readme [11.4K]

n = number of vibrations set in the string = 400 vibrations

t = total time taken for "n" vibrations set in the string = 4 second

f = frequency of the sound emitted due to vibrations set in the string


frequency of the sound emitted due to vibrations set in the string is given as

f = n/t

inserting the above values in the above formula

f = 400/4

f = 100 Hz

hence the frequency of sound comes out to be 100 Hz

4 0
4 years ago
Need help with two physics questions!
nikitadnepr [17]

1) The north component of the airplane velocity is 260 km/h.

2) The direction of the plane is 24^{\circ} north of east.

Explanation:

1)

In this problem, we have to resolve the velocity vector into its components.

Taking east as positive x-direction and north as positive y-direction, the components of the velocity along the two directions are given by:

v_x = v cos \theta

v_y = v sin \theta

where

v is the magnitude of the velocity

\theta is the angle between the direction of the velocity and the positive x-axis (the east direction)

For the airplane in this problem,

v = 750 km/h

\theta=20^{\circ}

So, the two components are

v_x = (750)(cos 20)=704.8 km/h

v_y = (750)(sin 20)=256.5 km/h

So, the component in the north direction is 256.5 km/h, so approximately 260 km/h.

2)

In this problem, we have to use vector addition.

In fact, the motion of the plane consists of two displacements:

- A first displacement of 220 km in the east direction

- A second displacement of 100 km in the north direction

Using the same convention of the same problem (x = east and y = north), we can write

d_x = 220 km

d_y = 100 km

Since the two vectors are perpendicular to each other, we can find their magnitude using Pythagorean's theorem:

d=\sqrt{d_x^2+d_y^2}=\sqrt{(220)^2+(100)^2}=241.7 km

And the direction is given by

\theta=tan^{-1}(\frac{d_y}{d_x})=tan^{-1}(\frac{100}{220})=24^{\circ} north of east.

Learn more about vectors here:

brainly.com/question/2678571

brainly.com/question/4945130

brainly.com/question/2678571

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

8 0
4 years ago
The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The
True [87]

Answer:

Explanation:

Capacitance of capacitor

= ε₀ A / d , ε₀ is permittivity of space , A is area of plate , d is distance between plates.

= 8.85 x 10⁻¹² x 2 x 10⁻³ / (6 x 10⁻³)

= 2.95 x 10⁻¹² F

Electric field E = V / d , V is potential difference

V = E x d

= 100 x 10³ x 6 x 10⁻³

= 600 V

Charge on the capacitor

= capacitance x potential difference

= 2.95 x 10⁻¹² x 600

= 17.7 x 10¹⁰ C

3 0
3 years ago
The average standard rectangular building brick has a mass of 3.10 kg and dimensions of 225 m x 112 m x 75 m. The gravitational
zzz [600]

Answer:

P=3.61\times 10^{-3}\ Pa

Explanation:

Given that,

Mass of a brick, m = 3.1 kg

The dimensions of the brick 225 m x 112 m x 75 m

We need to find the maximum pressure created by the brick. We know that, the force acting per unit area is called pressure exerted. It is given by the formula as follows :

P=\dfrac{F}{A}

F = mg

A = area with minimum dimensions i.e. 112 m x 75 m

Pressure is maximum when the area is least.

So,

P=\dfrac{mg}{A}\\\\P=\dfrac{3.1\times 9.8}{112\times 75}\\\\P=3.61\times 10^{-3}\ Pa

So, the maximum pressure created by brick is 3.61\times 10^{-3}\ Pa.

5 0
3 years ago
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