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Gnom [1K]
2 years ago
12

At summer camp, the duration of a basketball game is 3/4 of an hour. The camp counsellors have set aside 6 hours for basketball

games. They need to determine how many games can be played. James and Raquel both attempted to solve the problem and their work is shown below.
Problem: 6 dived by 3/4



Question 1
POSSIBLE POINTS: 5
Select the camp counselor that correctly solved the problem.

James

Raquel

Question 2
POSSIBLE POINTS: 5
Identify and describe the error in the incorrect counsellor's work. :

Mathematics
2 answers:
guapka [62]2 years ago
8 0
It’s raquel. hope that helped
Pavel [41]2 years ago
3 0
I do believe the answer would be Raquel
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JK=2x+5 and KL=3x-8 find JL
professor190 [17]

Answer:

Step-by-step explanation:

3x -8 = 2x + 5

x - 8 = 5

x = 13

3(13) - 8 + 2(13) + 5

39 - 8 + 26 + 5

31 + 31 = 62

4 0
3 years ago
What is the value of the expression when a = 5 and b = 2?
adell [148]
A=5\b=2
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7 0
3 years ago
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Vilka [71]

Answer:

with what??!!

Step-by-step explanation:

6 0
2 years ago
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The maximum value of 12 sin 0-9 sin²0 is: -​
jeka57 [31]

Answer:

4

Step-by-step explanation:

The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)

If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0

However, I will assume you meant the angle to be \theta rather than 0 which makes sense and proceed accordingly

We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0

The original function is

f(\theta) = 12sin(\theta) - 9 sin^2(\theta)

Taking the first derivative of this with respect to \theta and setting it equal to 0 lets us solve for the maximum (or minimum) value

The first derivative of f(\theta) w.r.t \theta is

                        12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right)

And setting this = 0 gives

12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right) = 0

Eliminating cos(\theta) on both sides and solving for sin(\theta) gives us

sin(\theta) = \frac{12}{18} = \frac{2}{3}

Plugging this value of sin(\theta) into the original equation gives us

12(\frac{2}{3}) - 9(\frac{4}{9} ) = 8 - 4 = 4

This is the maximum value that the function can acquire. The attached graph shows this as correct

3 0
1 year ago
3.006 rounded to the nearest tenth
Ann [662]
3.006 rounded to the nearest tenth is 3.0. This is due to the fact that the 6 rounded up will mean that the current 0 becomes 1, but this will not be carried to the tenth when rounding up.
3 0
3 years ago
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