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4 years ago

What is 9540000 in expanded form using exponents to show powers of 10

Mathematics

2 answers:

trapecia [35]4 years ago

6 0

Answer:

9,540,000 = 9 x $10^6$ + 5 x $10^5$ + 4 x $10^4$

Step-by-step explanation:

The given number is 9,540,000

Now let's write this expanded form using the place value chart.

= 9 x 1,000, 000 + 5x 100,000 + 4 x 10,000 + 0 x 1000 + 0 x 100 + 0 x 10 + 0 x 1

Here thousands place, hundreds place, tens place and one place are zero.

= 9 x $10^6$ + 5 x $10^5$ + 4 x $10^4$

Therefore, the answer is

9,540,000 = 9 x $10^6$ + 5 x $10^5$ + 4 x $10^4$

GalinKa [24]4 years ago

3 0

You might be interested in

Use the variation of parameters method to solve the DR y" + y' - 2y = 1

postnew [5]

Answer:

$y(t)\ =\ C_1e^{-2t}+C_2e^t-t\dfrac{e^{-2t}}{3}-\dfrac{1}{3}$

Step-by-step explanation:

As given in question, we have to find the solution of differential equation

$y"+y'-2y=1$

by using the variation in parameter method.

From the above equation, the characteristics equation can be given by

$D^2+D-2\ =\ 0$

$=>D=\ \dfrac{-1+\sqrt{1^2+4\times 2\times 1}}{2\times 1}\ or\ \dfrac{-1-\sqrt{1^2+4\times 2\times 1}}{2\times 1}$

$=>\ D=\ -2\ or\ 1$

Since, the roots of characteristics equation are real and distinct, so the complementary function of the differential equation can be by

$y_c(t)\ =\ C_1e^{-2t}+C_2e^t$

Let's assume that

$y_1(t)=e^{-2t}$ $y_2(t)=e^t$

$=>\ y'_1(t)=-2e^{-2t}$ $y'_2(t)=e^t$

and g(t)=1

Now, the Wronskian can be given by

$W=y_1(t).y'_2(t)-y'_1(t).y_2(t)$

$=e^{-2t}.e^t-e^t(-e^{-2t})$

$=e^{-t}+2e^{-t}$

$=3e^{-t}$

Now, the particular solution can be given by

$y_p(t)\ =\ -y_1(t)\int{\dfrac{y_2(t).g(t)}{W}dt}+y_2(t)\int{\dfrac{y_1(t).g(t)}{W}dt}$

$=\ -e^{-2t}\int{\dfrac{e^t.1}{3.e^{-t}}dt}+e^{t}\int{\dfrac{e^{-2t}.1}{3.e^{-t}}dt}$

$=\ -e^{-2t}\int{\dfrac{1}{3}dt}+\dfrac{e^t}{3}\int{e^{-t}dt}$

$=\dfrac{-e^{-2t}}{3}.t-\dfrac{1}{3}$

$=-t\dfrac{e^{-2t}}{3}-\dfrac{1}{3}$

Now, the complete solution of the given differential equation can be given by

$y(t)\ =\ y_c(t)+y_p(t)$

$=C_1e^{-2t}+C_2e^t-t\dfrac{e^{-2t}}{3}-\dfrac{1}{3}$

5 0

3 years ago

Suppose you observe a star orbiting the galactic center at a speed of 1300 km/skm/s in a circular orbit with a radius of 18 ligh

laila [671]

Answer: 1.1818^37 kg

Step-by-step explanation:

Given that:

Orbit speed = 1300 km/s

Radius (r) = 18 light days

Mass of object the star is orbiting :

Using the relation :

M = rv² / G

Where ; r = Radius in m ; v = velocity in m/s

G = 6.67 * 10^-11 = gravitational constant

18 light days in meters = 4.662 * 10^14 m

v = 1300km/s to m/s

v = (1300 * 1000)m /s = 1300000 m/s = 1.3 * 10^6 m/s

Hence ;

M = (4.662 * 10^14 * (1.3 * 10^6)^2 / (2/3) * 10^-10

M = (4.662 * 10^14) * (1.69 * 10^12) / (2/3) *10^-10

M = (7.87878 * 10^26) / 6.67 * 10^-11

= 1.1818^37 kg

7 0

3 years ago

What fraction of a year is 4 months?

MAVERICK [17]

Answer:

One third $\frac{1}{3}$

Step-by-step explanation:

A year has 12 months, which means that 4 months would be $\frac{4}{12}$ , but since both the numerator and denominator can be divided by 4 this fraction can be simplified to $\frac{1}{3}$

6 0

3 years ago

Eliza started the week with $274 in her bank account. This week she babysat for 16 hours and made $144.25. Eliza then went to th

elixir [45]

Hi. I hope this helps!

I believe the answer is 330.26 left.

1. First you add 274 and 144.25

You get 388.25

2. The. You subtract the amount of the video game from 388.25

You get 330.26

I hope this helps! Have a great day!

4 0

4 years ago

Please please help me out......... :)

Vika [28.1K]

Answer:

Step-by-step explanation:

The red graph is the graph of y = f(x) translated horizontally by 3 units

Given f(x) then f(x + a) is a horizontal shift of a units

• If a > 0 then shift to the left of a units

• If a < 0 then shift to the right of a units

Here f(x) has been shifted 3 units to the right, thus

y = f(x - 3) → B

7 0

3 years ago