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Nesterboy [21]
3 years ago
7

A group of workers can plant 5/8 acres in 4/5 days. What is the unit rate in acres per day?

Mathematics
1 answer:
Mila [183]3 years ago
3 0
In order to find the unit rate of acres per day, or in other words, how many acres can they plant in one day, you must divide 5/8, the number of acres planted, by 4/5, the number of days it took to plant. When you divide the two fractions, first set up an expression:
5/8<span>÷4/5

Then, to make things simpler, turn the division expression into a multiplication statement so that you have 5/8*5/4. Then multiply straight across and you get your answer as 25/32. This means that the workers can plant 25/32 acres per day.</span>
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If 2a+ 2/a =4, what is the value of 2a^2− 2/a^2 ?
aliina [53]

Answer:

0

Step-by-step explanation:

2a+ 2/a =4

Multiply each side by a to clear the fraction

a( 2a+ 2/a) =4*a

Distribute

2a^2 +2 = 4a

Subtract 4a from each side

2a^2 -4a +2 = 4a-4a

2a^2 -4a +2 =0

Divide by 2

2/2 a^2 -4a/2 +2/2 =0/2

a^2 -2a +1=0

Factor

(a-1) (a-1) =0

Using the zero product property

a=1

2a^2 -2/a^2

2(1)^2 -2/1^2

2-2

0

5 0
3 years ago
The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?
MaRussiya [10]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}

~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill

3 0
1 year ago
(Please answer! :) )
Anna [14]

Answer:

ok

Step-by-step explanation:

6 0
2 years ago
A 5 hour and 25-minute flight begins at 9:40 at what time will it end
motikmotik
Your answer is 3:05.

 You must add on to 9:40. So what I did was 9 + 5 = 14.
14 - 12 = 2.
So far it's 2:40.
25 minutes + 40. = 65.
Well there are 60 minutes in an hours. So 65 would be equal to 1H and 5min.
Now take that 1 hour. Add it to 2.
3 hours. And take your 5 minutes.
There! 3:05
7 0
3 years ago
Read 2 more answers
A corporate team-building event costs $19plus an additional $1 per attendee. How many attendees can there be, at most, if the bu
Mars2501 [29]

Answer:

There can be at most 12 attendees in a corporate team-building event.

Step-by-step explanation:

Let x denotes number of attendees in a corporate team-building event.

Fixed cost = $19

Cost charged per attendee = $1

Budget for the corporate team-building event = $31

Therefore,

19+1(x)\leq 31\\19+x\leq 31\\x\leq 31-19\\x\leq 12

So, there can be at most 12 attendees in a corporate team-building event.

8 0
3 years ago
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