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sp2606 [1]
3 years ago
8

Make x the subject 4x=y

Mathematics
1 answer:
Mandarinka [93]3 years ago
3 0

Answer:

x=y/4

Step-by-step explanation:

Simply divide by 4 to get x by itself

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Please help this is the last problem on my homework and I don’t understand how to do it
malfutka [58]
When the lines are parallel and angles are given, and since a straight line is 180°, the 2 angles of the line intersecting the parallel lines have to add up to be 180. Therefore,
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6 0
3 years ago
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Which equation represents a parabola that opens upward has a minimum at x=3 and has a line of symmetry at x=3
umka2103 [35]

Answer:

y=x^2-6x+5

Step-by-step explanation:

Let us consider the equation y=x^2-6x+5

For a quadratic equation in a standard form, y=ax^2+bx+c, the axis of symmetry is the vertical line x = \frac{-b}{2a}.

Here in this case we have, a=1, b=-6 , c =5

Putting the values we get,

x = \frac{-(-6)}{2\times 1} = \frac{6}{2} =3

We can see that the axis of symmetry is x=3 and the graph is giving minimum at x=3.

Therefore, the required equation is y=x^2-6x+5. Refer the image attached.


4 0
3 years ago
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Carlos just took a 40 question math test. He scored a 75%. How many questions did he get correct?
sergiy2304 [10]

Answer:

He missed 10 questions and got 30 right

Step-by-step explanation:

So we could do 0.75 times 40 and we would get 30

So he got 30 questions right which isn't too bad

8 0
2 years ago
Convert the polar coordinates (-3, -60°) to Cartesian coordinates.
notsponge [240]

Answer:

(1.5,-2.6)

Step-by-step explanation:

Given the polar coordinates (-3,60°).

Let our Cartesian coordinates be (x,y)

#We know that when converting the rectangular coordinates (x,y) to polar (r,θ), then:

r=\sqrt{x^2+y^2}\\\\\therefore r^2=x^2+y^2\\\\\theta=tan^{-1}(y/x)\\\therefore tan \theta=y/x

#Using the illustration above, we can express our polar coordinates as:

-3=\sqrt{x^2+y^2}\\\\-60\textdegree=tan^{-1}(y/x}

#Solve simultaneously to solve for x and y:

(-3)^2=x^2+y^2\ \ \ \ \ \ \ \ \ \ i\\\\tan(-0\texdegree)=y/x\ \ \ \ \ \ \ \ ...ii\\\\y=x\ tan(-60\textdegree)\ \ \ \ \ \ \ ...iii\\\\\#substitute\  y \ in\  i\\\\(-3)^2=x^2+(x \ tan (-60\textdegree))^2\\\\9=x^2+3x^2\\\\x=\sqrt{9/4}=1.5\\\\y=1.5\ tan(-60\textdegree)=-2.5981\approx-2.6

Hence, the Cartesian coordinates are (1.5,-2.6)

6 0
3 years ago
Bdhbdwbchdbvcwvdebvkbdebv kdbvjbwkv
Evgesh-ka [11]

Answer:6 i think

Step-by-step explanation:

6 0
3 years ago
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