An inequality that represents Denise's goal in terms of the number of hours spent running 'h'
Given :
Denise wants to burn at least 5000 calories a week through running.
she can burn 550 calories per hour
Let 'h' be the number of hours spent
In 1 hour she can burn 550 calories
In 'h' hours she can burn 550h calories
Given that she want to burn atleast 5000 calories in a week
Burn atleast 5000 calories means <=5000 calories
So , the inequality that represents Denise's goal is
calories burn in h hours <= 5000 calories
Learn more : brainly.com/question/381815
The solution would be like
this for this specific problem:
<span>V = ∫ dV </span><span>
<span>= ∫0→2 ∫
0→π/2 ∫ 0→ 2·r·sin(φ) [ r ] dzdφdr </span>
<span>= ∫0→2 ∫
0→π/2 [ r·2·r·sin(φ) - r·0 ] dφdr </span>
<span>= ∫0→2 ∫
0→π/2 [ 2·r²·sin(φ) ] dφdr </span>
<span>= ∫0→2 [
-2·r²·cos(π/2) + 2·r²·cos(0) ] dr </span>
<span>= ∫0→2 [
2·r² ] dr </span>
<span>=
(2/3)·2³ - (2/3)·0³ </span>
<span>= 16/3 </span></span>
So the volume of the
given solid is 16/3. I am hoping that these answers have satisfied
your query and it will be able to help you in your endeavors, and if you would
like, feel free to ask another question.
The x,y = -6, -5. Hope this helped, and have a great day! :D
Answer:
A and E
Step-by-step explanation:
The given problem shows a graph of a vertical line with an undefined slope, in which its equation is x = 3 (which matches Option A).
It is not considered a function because it has the same input for every given output. This means that regardless of its y-coordinate, its corresponding x-coordinate will always be x = 3.
The Vertical Line Test allows us to know whether or not a graph is actually a function. Remember that a function can only take on one output for each input. We cannot plug in a value and produce two output values. Since the graph represents a vertical line, it automatically fails the vertical line test. Therefore, it is not a function.
Because it is not a function, Options B, C, and D are invalid answers.
Hence, the correct answers are Options A and E.
X=4/log(2) Hope this helps!
