The answer here is after 3 minutes. The flat line on your temperature graph is where steam AND water are both present. As we go along the graph, the mixture of steam and water will turn into all water.
Hello There!
The law of conservation of mass states that <em>Matter/substances/energy can not be created or destroyed, it can only be transferred from state to state.</em>
Answer:
Part a)
U = 15.5 J
Part b)
h = 1.05 m
Part c)
v = 4.55 m/s
Explanation:
Part a)
Initial potential energy stored in the spring is given by
![U = \frac{1}{2}kx^2](https://tex.z-dn.net/?f=U%20%3D%20%5Cfrac%7B1%7D%7B2%7Dkx%5E2)
now we have
![k = 777 N/m](https://tex.z-dn.net/?f=k%20%3D%20777%20N%2Fm)
x = 20.0 cm
now from above formula we will have
![U = \frac{1}{2}(777)(0.20)^2](https://tex.z-dn.net/?f=U%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28777%29%280.20%29%5E2)
![U = 15.5 J](https://tex.z-dn.net/?f=U%20%3D%2015.5%20J)
Part b)
By mechanical energy conservation law we can say that initial spring potential energy stored = final gravitational potential energy at the top position
![\frac{1}{2}kx^2 = mgh](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dkx%5E2%20%3D%20mgh)
![15.5 = 1.5(9.8)h](https://tex.z-dn.net/?f=15.5%20%3D%201.5%289.8%29h)
![h = 1.05 m](https://tex.z-dn.net/?f=h%20%3D%201.05%20m)
So maximum height from gun is 1.05 m
Part c)
For muzzle velocity of the ball we can use the energy conservation again
According to which the final kinetic energy of the ball = initial spring energy stored in it
![\frac{1}{2}mv^2 = \frac{1}{2}kx^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%3D%20%5Cfrac%7B1%7D%7B2%7Dkx%5E2)
![(\frac{1}{2})(1.5 v^2) = 15.5](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B2%7D%29%281.5%20v%5E2%29%20%3D%2015.5)
![v = v = 4.55 m/s](https://tex.z-dn.net/?f=v%20%3D%20v%20%3D%204.55%20m%2Fs)
Answer:
0.6
Explanation:
Angular acceleration is equal to Net Torque divided by rotational inertia, which is the rotational equivalent to Newton’s 2nd Law. Therefore, angular acceleration is equal to 3.6/6 which is 0.6. Hope this helped!