K.E. = 1/2 mv²
K.E. is directly proportional to v^2
So, when K.E. increase by 2, K.E. increase by root. 2
v' = 1.41v
original v value was 3 so, final would be:
v' = 1.41*3 = 4.23
After round-off to it's tenth value, it will be:
v' = 4.2
So, option B is your answer!
Hope this helps!
Yes, but there is only 1 atom like that and is is hydrogen. Hydrogen is the only element that could have a nucleus with one proton and no neutrons exist.
Answer:
The RMS voltage across the resistor = 28 V
Explanation:
Capacitor: A capacitor is an electrical device that has the ability to store electrical charges in an electrical circuit. It is expressed in Farad (F)
Resistor: A resistor is an electrical device that oppose the flow of electric current in a circuit. It is expressed in ohms (Ω)
RMS Voltage : RMS voltage value of an alternating voltage is defined as that value of steady voltage which would dissipate heat at the same rate in a given resistance
Since the it is a series circuit, the total voltage is divided across the resistance and the capacitor.
Vt = V₁ + V₂...........................Equation 1
Where Vt = total Rms voltage = 120 V , V₁ = Rms voltage across the Capacitor = 92 V, V₂ = Rms voltage across the resistor.
Making V₂ the subject of the equation in equation 1 above,
V₂ = Vt - V₁ = 120 - 92
V₂ = 28 V.
The RMS voltage across the resistor = 28 V
The initial is where you are starting and the final postion is where the object ends up
Taking into account the definition of molarity, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 
.
<h3>Definition of molarity</h3>
Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
Molarity is expressed in units .
<h3>This case</h3>
In this case, you have:
- number of moles= 70 g×
= 0.7143 moles, where 98 g/mole os the molar mass of H₂SO₄ - volume= 0.28 dm³= 0.28 L (being 1 dm³= 1 L)
Replacing in the definition of molarity:
Solving:
<u><em>Molarity= 2.5510 </em></u>
Finally, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 .
Learn more about molarity:
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