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Lana71 [14]
2 years ago
12

A student carries a backpack for one mile. Another student carries the same backpack for two miles

Physics
1 answer:
Svetllana [295]2 years ago
3 0

Answer:

Compared to the first student, the second student did twice as much work as the first student.

Explanation:

The work done by the first student will be equal to the Force exerted by the backpack on the student carrying it multiplied by one mile (Distance).  The work done by the second student will be equal to the Force exerted by the backpack on the student carrying it multiplied by two miles (Distance).

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A 20-N force acts on an object with a mass of 2.0kg. what is the objects acceleration?
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A single-phase electrical load draws 600KVA at 0.6 power factor lagging. a) Find the real and reactive power absorbed by the loa
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Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

Explanation:

Given that,

Power factor = 0.6

Power = 600 kVA

(a). We need to calculate the reactive power

Using formula of reactive power

Q=P\tan\phi...(I)

We need to calculate the \phi

Using formula of \phi

\phi=\cos^{-1}(Power\ factor)

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Put the value of Φ in equation (I)

Q=600\tan(53.13)

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(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

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Q''=Q-Q'

Put the value into the formula

Q''=799.99-9.94

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Hence, (a). The reactive power is 799.99 KVAR.

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