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alina1380 [7]
3 years ago
13

Issac, BYU-Idaho student, found an old article in the school paper, the Scroll, that asserted that 11% of girls "wait for their

missionary". Now that some years have passed and the missionary age limits have changed, and Isaac wants to revisit the question and would like to estimate what proportion of girls "wait for their missionary". If he is willing to accept a margin of error of 3%, and a 90% confidence level, how many observations does he need in his sample
Mathematics
1 answer:
ololo11 [35]3 years ago
8 0

Answer: 151

Step-by-step explanation:

When the prior estimate of population proportion is available , then the formula for sample size:  n=p(1-p)(\dfrac{z^*}{E})^2

, where p= prior estimate of population proportion

z*= critical-value.

E= Margin of  error.

Let p be the proportion of of girls "wait for their missionary".

p = 11% =0.11

E= ± 0.03

The critical z-value corresponding to 90% confidence level = z*=1.645 [using z-table ]

Substitute all the values in the above formula , we get

Required sample size  :n=(0.11)(1-0.11)(\dfrac{(1.96)}{0.05})^2

\Rightarrow\ n=(0.11)(0.89)(39.2)^2

\Rightarrow\ n=(0.0979)(1536.64)\\\\\Rightarrow\ n=150.437056\approx151 [Rounded to next integer.]

Thus, the number of observations he needs in his sample = 151

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Answer:

175(130)^t) < 1200

Step-by-step explanation:

The occupancy is 1200 so it must me less than 1200 (<1200)

the number of people in at any time is 100% of the people in or 1.00

and it increases by 30%  or 0.30  (1.30)  

And it starts with 175 people (1.75)

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4 years ago
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4 0
3 years ago
In a tournament team A won 7 less games than Team B, and Team B won exactly three times as many games as team C. If If Team C wo
Mrac [35]
You can answer this by starting with the number of games team C won and then use this to represent how many teams B and A won.


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4 years ago
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slavikrds [6]

Answer:

Each person will pay $9.78

Step-by-step explanation:

Given that:

Amount of bill = $34

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3 years ago
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