Select the single best answer. When 2-heptyne was treated with aqueous sulfuric acid containing mercury(II) sulfate, two product
s, each having the molecular formula C7H14O, were obtained in approximately equal amounts. What are these two compounds
1 answer:
Answer:
heptan-3-one and heptan-2-one
Explanation:
In this case, we must remember what the products of this reaction are. An alkyne in the presence of HgSO4 and H2SO4 will produce a ketone. But, in the triple bond, we have two carbons, therefore the carbonyl group can be placed on any of the carbons of the triple bond.
In figure 1 we have the general reaction. At C = O it can be added to the carbon on the left (red carbon) or the carbon on the right (blue carbon).
Following this logic, for 2-heptyne the carbonyl group can be added to carbon 2 producing <u>heptan-2-one</u>. Similarly, the carbonyl group can be added to carbon 3 producing <u>heptan-3-one</u>. (See figure 2)
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The new concentration of the solution is 0.016 M
<h3>Dilution</h3>From the question, we are to determine the concentration of the new solution prepared from question 4.
NOTE: Question is provided below
From question 4, the concentration of the sodium chloride solution is 0.200M
Now, to determine the new concentration,
Using the dilution law
C₁V₁ = C₂V₂
Where
C₁ is the initial concentration
V₁ is the initial volume
C₂ if the final concentration
and V₂ is the final volume
Then,
C₁ = 0.200 M
V₁ = 10.00 mL
C₂ = ?
V₂ = 125.00 mL
Then,
0.200 × 10.00 = C₂ × 125.00
C₂ = 0.016 M
Hence, the new concentration of the solution is 0.016 M
Question 4:
Calculate the amount of solid sodium chloride needed to make 200.00 mL of a 0.200 M solution
Learn more on Dilution here: brainly.com/question/24881505