Answer:
(d) Why is the fuel cell in Question (c) described as an alkaline fuel cell? (e) Another type of fuel cell uses methanol instead of hydrogen.
Explanation:
Answer:
There will be 143,67g CO2 produced
Explanation:
2 C6H6 + 15 O2 → 12 CO2 + 6 H2O
(42,5 g C6H6) / (78.1124 g C6H6/mol) = 0.54408775 mole C6H6
(113.1 g O2) / (31.9989 g O2/mol) = 3.534496 moles O2
0.54408775 mole of C6H6 would react completely with 0.54408775 x (15/2) = 4.080658 mole O2, but there is more O2 present than that, so O2 is in excess and C6H6 is the limiting reactant.
(0.54408775 mol C6H6) x (12/2) x (44.0096 g/mol) = 143.67 g CO2
Answer:
The answer is "Option A"
Explanation:
At 3300 cm-1, the wide region is equal to OH. It is a possible group of alcoholic features that includes drugs. In the given choices option a is correct that's the structure can be defined in attachment file please find it, and the wrong choice can be defined as follows:
- In choice B, It is wrong because it doesn't include OH.
- In choice C, it uses the triple bond, that's why it is wrong.
- In choice D, it uses the two bonds, that's why it is wrong.
- In choice E, it uses the characteristic bond, that's why it is wrong.
Answer:
D. h = ( P - Po ) / ρg
Explanation:
clearing h:
⇒ P - Po = ρgh
⇒ ( P - Po ) / ( ρg ) = h