Nitrosyl fluoride has the chemical formula NOF. Nitrogen has five valence electrons, oxygen has six, and fluorine has seven. Com
plete the Lewis structure for this covalent compound.
1 answer:
Answer:
Watch the attached image, please.
Explanation:
To complete the Lewis structure for this covalent compound, you have to draw all the atoms with their valence electrons.
The drew has the nitrogen in the center and the fluoride and oxygen in the sides.
Each one of these atoms has to complete the octet rule, which is the ruler who says that all the atoms want to reach to have eight electrons to feel "stable".
For that reason, you have to arrange the atoms to comply with this rule.
You might be interested in
Answer:
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:
Thus, by combining them, we obtain:
Which is related to the general line equation:
Whereas:
It means that we answer to the blanks as follows:
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.
Regards!
Answer:
Explanation:
1. find the molar mass (amu) of each element and add them to get the whole molar mass.
2. divide the 1 element molar mass with the whole molar mass
3. multiple by 100 and that gives you the % composition.
<h2><u><em>56-57: NaCl</em></u></h2>1. Na(22.99amu) + Cl (35.453amu)=58.443
2(Na): = .393
2(Cl): = .607
3(Na): .393 * 100=39.3%
3(Cl): .607 * 100= 60.7%
<h2><u>58-60 </u>1. K: (39.098)(2)=78.196
_ C: (12.011)(1)= 12.011
_O: (15.99)(3) = 47.997
78.196+12.011+47.997= 138.204
2:K: = .566 <u>Step </u>3: (.566)(100)= 56.6%
2: C: = .087 <u>Step 3</u>: (.087)(100)= 8.7%
2: O: = .347 <u>Step 3</u>: (.347)(100) = 34.7%
1. Fe (55.845)(3)= 167.535
_ O (15.999)(4) = 63.996
167.535+63.996=231.531
2: Fe: = .724 Step 3: (.724)(100)= 72.4%
2: O : = .276 Step 3: (.276)(100) = 27.6%
1.
C(12.011*3)=36.033
H(1.008*5)=5.04 + (1.008*3)=3.024 so its 8.064
O(15.999*3)=47.997
add them: 92.094
2: C: = .391 Step 3: (.391)(100) = 39.1%
2: H: = .088 step 3: (.088)(100) = 8.8%
2: O: = .521 step 3: (.521)(100) = 52.1%