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Semmy [17]
4 years ago
5

The symbol for the hydroxide ion is _____. H + H 3O - H(OH) OH -

Chemistry
2 answers:
erastova [34]4 years ago
8 0
Your answer is D, OH-.
Nutka1998 [239]4 years ago
4 0
Your answer is D OH-
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How many grams are there in 3. 4 x 1024 molecules of nh3.
nadezda [96]

Answer:

69,632 grams

explanation

number of molecules =mass\molemass

nh3 14 +2×3=20

3.4×1024=m/20

cross multiply

grams =69,632

7 0
3 years ago
Carbon dioxide was used by early plants so that they could
IgorLugansk [536]

Answer:

Plants use carbon dioxide for photosynthesis

Explanation:

They take it in, and chemically combined it with water to form glucose and oxygen

8 0
3 years ago
In an eluent solution of 70% hexanes and 30% ethyl acetate, compound A moves farther on the TLC plate than compound B. Compound
8090 [49]

Answer:

it means compound A is <u>less</u> polar than compound B

Explanation:

It is sure that the more polar the solvent, the faster compounds elute, regardless of the compounds polarity. This means changing the solvent polarity cannot change the order compounds elute from a TLC or column. This may seem non intuitive, as it would seem that a polar solvent would move a polar compound farther than a nonpolar compound.

6 0
3 years ago
What is The atomic mass number of tin
san4es73 [151]

Answer:

50

Explanation:

The atomic number is 50

3 0
3 years ago
Read 2 more answers
A 4.215 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of oxygen gas, producing 9.58
Scilla [17]

Answer:

\% O=27.6\%

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}  =0.218molC

- Moles of hydrogen are contained in the 3.922 grams of water:

n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO

Finally, we compute the percent by mass of oxygen:

\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%

Regards.

5 0
4 years ago
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