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4 years ago

The symbol for the hydroxide ion is _____. H + H 3O - H(OH) OH -

Chemistry

2 answers:

erastova [34]4 years ago

8 0

Your answer is D, OH-.

Nutka1998 [239]4 years ago

4 0

Your answer is D OH-

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Fluoride ion is poisonous in relatively low amounts: 0.2 g of F- per 70 kg of body weight can cause death. Nevertheless, in orde

svetoff [14.1K]

Answer:

$\boxed{\text{(a) 14 L; (b) 711 kg}}$

Explanation:

(a) Litres of water

$\text{Mass of F}^{-} = 8.5 \times 10^{7}\text{ gal} \times \dfrac{\text{0.2 mg F}^{-}}{\text{1 kg}} = \textbf{14 mg F}^{-}\\\\\text{Volume of water} = \text{14 mg F}^{-} \times \dfrac{\text{1 L water}}{\text{1 mg F}^{-}} = \textbf{14 L water}\\\\\text{The person would have to consume $\boxed{\textbf{14 L}}$ of water per day}$

(b) Mass of NaF

$\text{Volume} =8.5 \times 10^{7} \text{gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} = 3.22 \times 10^{8}\text{ L}\\\\\text{Milligrams of F}^{-} = 3.22 \times 10^{8}\text{ L} \times \dfrac{\text{ 1 mg F}^{-}}{\text{1 L}} = 3.22 \times 10^{8}\text{ mg F}^{-}\\\\\text{kilograms of F}^{-} = 3.22 \times 10^{8}\text{ mg F}^{-} \times \dfrac{\text{1 mg F}^{-}}{10^{6}\text{kg F⁻}} = \text{322 kg F}^{-}$

1 kmol of NaF (41.99 kg) contains 19.00 kg of F⁻.

$\text{Kilograms of NaF}= \text{322 kg F}^{-} \times \dfrac{\text{41.99 kg NaF}}{\text{19.00 kg F}^{-}} = \text{711 kg NaF}\\\\\text{It will take } \boxed{\textbf{711 kg}} \text{ of NaF to treat the reservoir}$

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3 years ago

Read 2 more answers

Show the curved-arrow mechanism for the Claisen condensation of ethyl ethanoate treated with ethoxide ion. Include all formal ch

Anna [14]

Answer:

See explaination

Explanation:

Please kindly check out the attached files for the curved-arrow mechanism for the Claisen condensation of ethyl ethanoate treated with ethoxide ion.

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3 years ago

How are elements in the same group similar

Georgia [21]

All the elements in one group have the same number of valence electrons.

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3 years ago

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Help ASAP!!!!!!!!!!!!!!!!!!!!!!!!!

BartSMP [9]

Answer:

ok .

Explanation:

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3 years ago

Question 19 Write a balanced half-reaction for the oxidation of gaseous nitrogen dioxide to nitrate ion in acidic aqueous soluti

Alexxx [7]

Answer:

This will be the balanced half reaction:

NO₂(g) + H₂O (l) → NO₃⁻(aq) + 1 e⁻ + 2H⁺ (aq)

Explanation:

In acidic medium, the redox balance has to be done as this way.

As it is an oxidation, we know that oxidation state has increased.

NO₂(g) → NO₃⁻(aq) + 1 e⁻

Nitrogen in NO₂ acts with +4; in the nitrate, N acts with +5

The nitrogen has released 1 electron.

As we are in acidic medium, we must complete with water, in the same side, as we have less oxygens and in the opposite side, with protons to balance the H. This will be the balanced half reaction:

NO₂(g) + H₂O (l) → NO₃⁻(aq) + 1 e⁻ + 2H⁺ (aq)

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3 years ago