Question

A drawer has some red ,green and blue marbles.there are 33 marbles . there are 4 times as many red marbles as green marbles.there are half as many blue marbles as green marbles.
how many blue marbles are in the drawer?

Answer 1

$g-green\ marbles\\r-red\ marbles\\b-blue\ marbles\\g+r+b=33\\\\4g-red\ marbles\\\frac{1}{2}g-blue\ marbles\\\\g+4g+\frac{1}{2}g=33\\\\5\frac{1}{2}g=33\\\\\frac{11}{2}g=33\ \ \ \ /\cdot\frac{2}{11}\\\\g=3\\\\Answer:b=\frac{1}{2}g\to b=\frac{1}{2}\cdot6=3$

Answer 2

Answer:

The number of blue marbles be 3.

Step-by-step explanation:

As given

A drawer has some red ,green and blue marbles.

There are 33 marbles .

there are 4 times as many red marbles as green marbles.

Let us assume that the number of green marbles be g .

Than Red marbles = 4g

There are half as many blue marbles as green marbles.

Than

$Number\ of\ blue\ marbles =\frac {Number\ of\ green\ marbles}{2}$

$Number\ of\ blue\ marbles =\frac{g}{2}$

Than the equation becomes

$g + 4g + \frac{g}{2} = 33$

Than simplify the above

$2g + 8g + g = 33\times 2$

$11g = 66$

$g= \frac{66}{11}$

g = 6

$Number\ of\ blue\ marbles =\frac{6}{2}$

Number of blue marbles = 3

Therefore the number of blue marbles be 3 .