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3 years ago

6

Is 0.005 a significant number

2 answers:

Keith_Richards [23]3 years ago

7 0

I would go with yes. For most applications, P values of 0.05 or less are considered significant. If your values is 0.005, there is only a 0.5% chance of that result occurring due to chance.

Marrrta [24]3 years ago

3 0

It depends what the number means.
If it's the number of centimeters of volcanic ash per minute piling up in your yard, it's a very significant number.
If it's the number of inches of snow your city got last Winter, then it's totally INsignificant.

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Marizza181 [45]

1. because they have the same numbers of protons and electrons.

2. by the number of its protons and neutrons

3. yes, because the isotopes of an element also have the same number of electrons.

7 0

3 years ago

In 1985, Said Aouita set the world record for the 1500m race in a time of 3 minute 29.46 second ? What was his average speed ?

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8 0

3 years ago

A rabbit trying to escape a fox runs north for 8.0 m, darts northwest for 1.0 m, then drops 1.0 m down a hole into its burrow. W

Andrews [41]

Answer: The net displacement is 6.40meters

Explanation:

7 0

3 years ago

A heater is being designed that uses a coil of 14-gauge nichrome wire to generate 300 W using a voltage of V = 110 V . How long

Mazyrski [523]

Answer:

The length of the wire is 83.2 m.

Explanation:

Given that,

Power of heater, P = 300 W

Voltage, V = 110 V

The resistivity of nichrome wire is, $\rho=100\times 10^{-8}\ \Omega-m$

The electric power of a wire is given by :

$P=\dfrac{V^2}{R}\\\\R=\dfrac{V^2}{P}\\\\R=\dfrac{(110)^2}{300}\\\\R=40.34\ \Omega$

Area of cross section of the wire is :

$A=\pi r^2\\\\A=\pi (0.000815)^2\\\\A=2.08\times 10^{-6}\ m^2$

Resistance of a material is given by :

$R=\rho \dfrac{L}{A}\\\\L=\dfrac{RA}{\rho}\\\\L=\dfrac{40\times 2.08\times 10^{-6}}{10^{-6}}\\\\L=83.2\ m$

So, the length of the wire is 83.2 m. Hence, this is the required solution.

5 0

3 years ago

A jet airplane has a velocity of 1145 knots. A knot is 1 nautical mile (nm)/hr. A nautical

Tanya [424]

Answer:

1 m = 39.37 in = 39.37/12 ft = 3.28 ft

V = 1145 k/hr = 1145k/hr * 6076 ft/k = 6957020 ft / hr

V = 6957020 ft/hr / 3600 s/hr = 1933 ft/sec

V = 1933 ft/sec / (3.28 ft / m) = 589 m/s

Check:

88 ft/sec = 60 mph

(1145 k/hr * 6076 ft / k) 3600 sec/hr = 1933 ft/sec = 589 m/s

1933 ft/sec / (88 ft/sec) * 60 mph = 1318 mph

Also, 1318 / 1145 = 6076 / 5280 as it should

4 0

3 years ago