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konstantin123 [22]
3 years ago
8

Define a machine in the physics subject ​

Physics
1 answer:
mezya [45]3 years ago
3 0

Answer:

Explanation:

Different Parts of an Electric Motor and Their Function

A simple motor has the following parts:

A power supply – mostly DC for a simple motor

Field Magnet – could be a permanent magnet or an electromagnet

An Armature or rotor

Commutator

Brushes

Axle

Power Source: A simple motor usually has a DC power source.  It supplies power to the motor armature or field coils.

Commutator: It is the rotating interface of the armature coil with a stationary circuit.

Field Magnet: The magnetic field helps to produce a torque on the rotating armature coil by virtue of Fleming’s left-hand rule.

Armature Core: Holds the armature coil in place and provides mechanical support.

Armature Coil: It helps the motor to run.

Brushes: It is a device that conducts current between stationary wires and moving parts, most commonly the rotating shaft.

What Is The Working Principle of An Electric Motor?

The working of an electric motor is based on the fact that a current carrying conductor produces a magnetic field around it. To better understand, imagine the following situation.

Take two bar magnets and keep the poles facing each other with a small space in between. Now, take a small length of a conducting wire and make a loop. Keep this loop in between the space between the magnets such that it is still within the sphere of influence of the magnets. Now for the last bit. Connect the ends of the loop to battery terminals.

Once electricity flows through your simple circuit, you will notice that your loop “moves”. So why does this happen? The magnetic field of the magnets interferes with that produced due to electric current flowing in the conductor. Since the loop has become a magnet, one side of it will be attracted to the north pole of the magnet and the other to the south pole. This causes the loop to continuously rotate. This is the principle of working of electric motor.

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A boat race runs along a triangular course marked by buoys A, B, and C. The race starts with the boats headed west for 3700 mete
ale4655 [162]

Answer:

The  last two bearings are

49.50° and 104.02°

Explanation:

Applying the Law of cosine (refer to the figure attached):

we have

x² = y² + z² - 2yz × cosX

here,

x, y and z represents the lengths of sides opposite to the angels X,Y and Z.

Thus we have,

cos X=\frac{x^2-y^2-z^2}{-2yz}

or

cos X=\frac{y^2 + z^2-x^2}{2yz}

substituting the values in the equation we get,

cos X=\frac{2900^2 + 3700^2-1700^2}{2\times 2900\times 3700}

or

cos X=0.8951

or

X = 26.47°

similarly,

cos Y=\frac{1700^2 + 3700^2-2900^2}{2\times 1700\times 3700}

or

cos Y=0.649

or

Y = 49.50°

Consequently, the angel Z = 180° - 49.50 - 26.47 = 104.02°

The bearing of 2 last legs of race are angels Y and Z.

7 0
3 years ago
If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front o
andrezito [222]
The answer is

18 / x = 12 / 4 
12x = 72
x = 6mm
4 0
3 years ago
Read 2 more answers
Find the radioactivity of a 1 g sample of 226Ra given that <img src="https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D1620" id="TexFormul
dangina [55]

Answer:

Explanation:

No of atoms of Ra in 1 g of sample = 6.023 x 10²³ / 226

N = 2.66 x 10²¹

disintegration constant λ = .693 / half life

half life = 1620 x 365 x 60 x 60 x 24 = 5.1 x 10¹⁰ s

disintegration constant λ = .693 / 5.1 x 10¹⁰

radioactivity dn / dt = λN

= (.693 / 5.1 x 10¹⁰ )  x 2.66 x 10²¹

= .3614 x 10¹¹ per sec

= 3.614 x 10¹⁰ / s

6 0
3 years ago
object is placed 15cm in front of a plane mirror. If the mirror is moved further 5cm away from the object and the image is​
solong [7]

Answer:

The image will most likely be 20cm in front the mirror since the mirror was placed further 5cm.

4 0
3 years ago
Read 2 more answers
Two out-of-tune flutes play the same note. One produces a tone that has a frequency of 248 Hz, while the other produces 288 Hz.
zaharov [31]

Answer:

F = 268 Hz

Explanation:

The beat frequency is given as:

Beat Frequency = |Frequency 1 - Frequency 2|\\|

So, for the first flute and tuning fork:

20 Hz = |248 Hz - F|

where,

F = Frequency of tuning fork

F = 248 Hz ± 20 Hz

F = 268 Hz (OR) 228 Hz

Now, for the second flute and tuning fork:

20 Hz = |288 Hz - F|

where,

F = Frequency of tuning fork

F = 288 Hz ± 20 Hz

F = 268 Hz (OR) 308 Hz

Since, 268 Hz is common from both calculations. Therefore, it will be the frequency of the tuning fork.

<u>F = 268 Hz</u>

3 0
3 years ago
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