The correct option is third.
This question is essentially asking if the ratios of number 5:6 = 3:4
if we want to check, we can do cross multiplication.
So we are trying to find out if 5(4) = 3(6).
5(4) = 20 and 3(6) = 18.
so, ![5:6 \neq 3:4](https://tex.z-dn.net/?f=5%3A6%20%5Cneq%203%3A4)
The correct option is third.
- No, because the numbers in the given ratio must be multiplied by the same number.
learn more about ratios of numbers here:
brainly.com/question/17571940
#SPJ1
Answer:
the answer is A.
Step-by-step explanation:
i just took the test ;)
Answerj, C v v .
Step-by-step explanation:
Answer:
![3\sqrt{6x^2} = 3x\sqrt{6}](https://tex.z-dn.net/?f=3%5Csqrt%7B6x%5E2%7D%20%3D%203x%5Csqrt%7B6%7D)
Step-by-step explanation:
Given
![3\sqrt{6x^2](https://tex.z-dn.net/?f=3%5Csqrt%7B6x%5E2)
Required
Express as a radical
Split
![3\sqrt{6x^2} = 3\sqrt{6} * \sqrt{x^2](https://tex.z-dn.net/?f=3%5Csqrt%7B6x%5E2%7D%20%3D%203%5Csqrt%7B6%7D%20%2A%20%5Csqrt%7Bx%5E2)
![\sqrt{x^2} = x](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2%7D%20%3D%20x)
So:
![3\sqrt{6x^2} = 3\sqrt{6} * x](https://tex.z-dn.net/?f=3%5Csqrt%7B6x%5E2%7D%20%3D%203%5Csqrt%7B6%7D%20%2A%20x)
This gives:
![3\sqrt{6x^2} = 3x\sqrt{6}](https://tex.z-dn.net/?f=3%5Csqrt%7B6x%5E2%7D%20%3D%203x%5Csqrt%7B6%7D)
Answer:
72
Step-by-step explanation: