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ikadub [295]
3 years ago
7

A plane traveled for a total of 1,190 miles over the course of 5 hours. Heading east, the plane traveled at an average speed of

266 miles per hour, and heading north, it traveled at an average speed of 196 miles per hour. For how many hours was the plane heading east?
Mathematics
1 answer:
bezimeni [28]3 years ago
8 0
Two equations are:
Te is time east
Tn is time north

Te + Tn = 5 hours
266Te +196Tn = 1190 is the distance equation

Solve these two equations and
Te = 3 hours and Tn= 2 hours
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Unit 3, Lesson 7
aksik [14]

Answer:

Find the complete table in attached file.

Step-by-step explanation:

Find the Incomplete table in attached file

Given:

A car travels 55 miles per hour for 2 hours.

So the speed of the car 55 miles per hour is constant for 2 hours.

Using speed  formula.

Speed=\frac{distance}{time}

Second row.

From the second row of the table time = \frac{1}{2}=0.5\ sec and speed is constant speed = 55\ mi/hr, so we need to find only distance.

Speed=\frac{distance}{time}

55=\frac{distance}{0.5}

distance = 55\times 0.5

distance = 27.5\ mi

Third row.

From the third row of the table time =1\frac{1}{2}=\frac{3}{2} = 1.5\ sec and speed is constant speed = 55\ mi/hr, so we need to find only distance.

Speed=\frac{distance}{time}

55=\frac{distance}{1.5}

distance = 55\times 1.5

distance = 82.5\ mi

Fourth row.

From the fourth row of the table distance =110\ miles and speed is constant speed = 55\ mi/hr, so we need to find time.

Speed=\frac{distance}{time}

time=\frac{distance}{speed}

time=\frac{110}{55}

time = 2\ sec

Therefore we complete the table from the above calculation.

8 0
3 years ago
What is the value of x in the equation –x = 4 – 3x + 6?
Nataly [62]
Remember you can do anything to an equaiton as long as you do it to both sides


-x=4-3x
add 3x both sides
3x-x=4+3x-3x
2x=4+0
2x=4
divide 2
2x/2=4/2
2/2x=2
1x=2
x=2
7 0
3 years ago
Read 2 more answers
GIVING BRAINLIEST!! HELP PLEASE!! you don't have to make it perfect. (no links/spam/or stealing points. i will report your accou
choli [55]
<h2>Answer:</h2>

C = 2πr

r = C/2π ...(1)

A = πr²

A = π(C/2π)² = πC²/4π²

A = C²/4π.

<u>Correct choice</u> - [A] A = C²/4π.

6 0
2 years ago
The length of a rectangular is 7/10 ft .and the width is 1/5ft what is the perimeter
Blababa [14]
<h3>Answer:</h3>

\huge\boxed{1 \frac{4}{5}\ \text{ft}}

<h3>Explanation:</h3>

Change \frac{1}{5} so that is has a common denominator.  \frac{1*2}{5*2}=\frac{2}{10}

Make an equation.  \frac{7+7+2+2}{10}

Add.  \frac{14+4}{10}

Add.  \frac{18}{10}

Divide both sides by 2.  \frac{9}{5}

Convert to a mixed number.  1 \frac{4}{5}

4 0
2 years ago
Read 2 more answers
Can anyone please help me with this ?
djverab [1.8K]

Answer:

The distance from point A to the top of the building is 5\sqrt{2} feet

The Height of the Skyscraper is 5 feet

Step-by-step explanation:

Given

Let Top point of building be point C

Also Let Base of the building be point  B

Distance from point A to base B of the building AB= 5 feet

∴ It makes a Right angle triangle

Also ∠ACB = 45°

Also tan 45° = 1

Now tan ∠ACB =\frac{AB}{BC}

∴ AB= BC =5 feet

The Height of the Skyscraper is 5 feet

Now Triangle ABC is right angle triangle with right angled at B

So by Pythagoras theorem

AC= \sqrt{AB^2+BC^2}=\sqrt{5^2+5^2} =\sqrt{50} =\sqrt{25\times2} =\sqrt{5^2\times2}=5\sqrt{2}

The distance from point A to the top of the building is 5\sqrt{2} feet

5 0
3 years ago
Read 2 more answers
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