The trial and error method is used to find an initial factor:
If we let f(x) = x³ - x² - 24x - 36 and all we have to do is sub' in values of x until
f(x) = 0, we can use this to find an initial factor by the factor theorem:
f(1) = (1)³ - (1)² - 24(1) - 36 = -60
f(2) = (2)³ - (2)² - 24(2) - 36 = -80
f(5) = (5)³ - (5)² - 24(5) - 36 = -56
*** f(6) = (6)³ - (6)² - 24(6) - 36 = 0 ***
f(6) = 0 so (x - 6) is a factor of f(x).
This means that: f(x) = x³ - x² - 24x - 36 = (x - 6)(ax² + bx + c).
To find a,b and c, use long division (or inspection) to divide x³ - x² - 24x - 36 by x - 6.
The other 2 factors of f(x) can then be found by factorizing the
ax² + bx + c quadratic the way you would with any other quadratic (i.e. by quadratic formula, CTS or inspection).
W+d=869
w=d-81
plug in
(d-81)+d=869
2d-81=869
+81 both sides
2d=950
÷2 both sides
d=475
dryer cost $475
let's check w=475-81
w=394
475+394=869
869=869
the solution is true :)
Hey!
So before trying to figure out the equation of the line, lets change -3y+4x = 9 into slope-intercept form:
-3y + 4x = 9
-3y = -4x + 9
y = (4/3)x - 3
Now that you have the equation in slope-intercept form we can find the equation of the line parallel to this. One thing that we are given from this equation is the slope of the line, the slope for two parallel lines are the same. So we know that the slope of the line is 4/3. We are also given another point on the line and we can plug this point in for y and x to find the y-intercept or b:
6 = (4/3)(-12) + b
6 = -16 + b
22 = b
Now that we know b, we have both the y-intercept and the slope so our equation would be:
y = (4/3)x + 22
Answer:
ma'am or sir... there is no picture attached... but whats the question?
Step-by-step explanation:
