Terminal velocity is the velocity at which a falling body experience
when its weight is equal to the force resistance of force opposing the
fall.
At terminal velocity the acceleration of the body is zero,
which implies that the value of the this velocity is a uniform.
Answer:
Liquid's index of refraction, n₁ = 1.27
Explanation:
It is given that,
The critical angle for a liquid in air is,
We have to find the refractive index of the liquid. Critical angle of a liquid is defined as the angle of incidence in denser medium for which the angle of refraction is 90°.
Using Snell's law as :
Here,
Where
n₂ = Refractive index of air = 1
n₁ = refractive index of liquid
So,
n₁ = 1.269
or n₁ = 1.27
Hence, the refractive index of liquid is 1.27
Answer:
Your friend is 2.143 blocks from the restaurant.
You are 2.857 blocks from the restaurant.
Explanation:
Let t be the time both you and your friend take to walk to the restaurant.
The distance (m) from your building to the restaurant is your walking time t times your speed v1
Similarly the distance (m) from your friend building to the restaurant:
Let b be the length (in m) of a block, the total distance of 5 blocks is 5b
So your friend are 2.143b meters from the restaurant, since each block is b meters long, 2.143b meters would equals to 2.143b/b = 2.143 blocks. And you are 5 - 2.143 = 2.857 blocks from the restaurant.
Answer:
20% of the human body float above the surface in the dead sea.
Explanation:
Given data,
The human density after inhaling, d₁ = 945 kg/m³
The human density after exhaling, d₂ = 1020 kg/m³
Therefore the average human density, d = 982.5 kg/m³
The density of the dead sea, D = 1230 kg/m³
The percentage of density of human body to the dead sea is,
P % = (982.5 / 1230) x 100 %
= 80 %
Therefore, the human body has 80% of dead sea density.
Hence, 20% of the human body float above the surface in the dead sea.