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Slav-nsk [51]
3 years ago
6

Help!! I’ll give brainliest! Match the changes in sound wave properties with their effects on an observer.

Physics
1 answer:
aivan3 [116]3 years ago
5 0
The answers are:
A:1
B:2
C:3

In short, they are already arranged. 

<em>Pitch </em><em />is defined as the sensation of a frequency. A high frequency corresponds to a high pitch. Low frequency corresponds to low pitch. So it is right to assume that rising frequency will cause a rising pitch. 

<em>Amplitude </em> is defined by the loudness of sound. It is the size of a vibration. The bigger the vibration is, the louder the sound it will produce. So it is safe to say that rising amplitude will result in rising volume. 

<em>Wavelength</em><em> </em>is the distance between the trough of one wave and the trough of the next wave; or the crest of one wave and the crest of the next wave. Short wavelengths mean more waves pass through a certain point at a certain time. As a result, shorter waves create higher frequencies. Longer waves, on the other hand, create lower frequencies. And using the definition of pitch above, we can then say that longer wavelengths will result in declining pitch. 



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Will mark brainliest. TRUE OR FALSE. the acceleration due to gravity is caused by a field force
choli [55]

Answer:

Yes, It is true.

The acceleration due to gravity is caused by field force.

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Which factors could be potential sources of error in the experiment? Check all that apply.
mote1985 [20]

Answer:

1. energy lost in the lever due to friction

3. visual estimation of height of the beanbag

5. position of the fulcrum for the lever affecting transfer of energy

Explanation:

Edge 2021

8 0
3 years ago
Read 2 more answers
n outer space, a constant net force with a magnitude of 140 N is exerted on a 32.5 kg probe initially at rest. A) What accelerat
musickatia [10]

Answer:

a) 4.31 m/s²

b) 215.5 m

Explanation:

a) According to Newton's first law of motion

The net force applied to particular mass produced acceleration, a, according to

F = ma

F = 140 N

m = 32.5 kg

a = ?

140 = 32.5 × a

a = 140/32.5 = 4.31 m/s²

b) Using the equations of motion, we can obtain the distance travelled by the object in t = 10 s

u = initial velocity of the probe = 0 m/s (since it was initially at rest)

a = 4.31 m/s²

t = 10 s

s = distance travelled = ?

s = ut + at²/2

s = 0 + (4.31×10²)/2 = 215.5 m

7 0
3 years ago
A Heavy crate applied a force of 1500 N on a 25m2 piston. What force needs to be applied on a 0.8m2 piston to lift the crate?
Aleks04 [339]
25/1500 is equal to 0.8/x
0.8*1500 is equal to 1200
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7 0
3 years ago
Read 2 more answers
A cat dozes on a stationary merry-go-round, at a radius of 5.7 m from the center of the ride. Then the operator turns on the rid
tatyana61 [14]

Answer:

0.76

Explanation:

we are given:

radius (r) =5.7 m

speed (s) = 1 revolution in 5.5 seconds

acceleration due to gravity (g) = 9.8 m/s^{2}

coefficient of friction (Uk) = ?

 we can get the minimum coefficient of friction from the equation below

centrifugal force = frictional force

m x r x ω^{2} = Uk x m x g

r x ω^{2} = Uk x g

Uk = \frac{ r x ω^{2} }{g}

where ω (angular velocity) = \frac{2π}{time}

= \frac{2π }{5.5} = 1.14

Uk = \frac{ 5.7 x 1.14^{2} }{9.8} = 0.76

6 0
3 years ago
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